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Aleksandr [31]
3 years ago
3

8. A 0.500 kg model rocket is initially pushed upwards by a thrust force of 15N. If the force of air resistance is 1.00 N, what

is the initial acceleration of the rocket?
Physics
2 answers:
Sphinxa [80]3 years ago
8 0
Resultant force = ma

15N - 1N = 0.5kg(a)
a = 14/0.5
a = 28 m/s2
algol133 years ago
6 0

Answer:

a = 18.19 m/s^{2}

Explanation:

Given

Mass of the rocket m = 0.500 kg

upward force F_{up} = 15 N

Air Resistance F_{Res} = 1.00 N

Solution

Net force = Upward forces - downward forces

Net force = Upward force - (air resistance + weight)

F_{net} = x_{up} -(F_{Res} +mg )\\\\F_{net} = 15 -( 1 + 0.5 \times 9.81)\\\\F_{net} = 15 - (1+ 4.905)\\\\F_{net} = 9.095

Net acceleration

a = \frac{F_{net} }{m} \\\\a = \frac{9.095 }{0.5}\\\\a = 18.19 m/s^{2}

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