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Delvig [45]
3 years ago
13

A Ford Mustang weighs about 3500 pounds, and can accelerate from 0-60 MPH in about 5 seconds. What force is responsible for this

acceleration? What is its approximate magnitude?
Physics
1 answer:
Hunter-Best [27]3 years ago
5 0

We will apply the concepts related to Newton's second law. At the same time we will convert everything to the system of international units.

m = 3500lb = 1587.57kg

The values of the velocities are,

\text{Initial Velocity} = V_i = 0

\text{Final Velocity} = V_f = 60mph = 26.822m/s

We know that the acceleration is equivalent to the change of the speed in a certain time therefore

a = \frac{v_f-v_i}{t}

a = \frac{26.822-0}{5}

a = 5.36m/s^2

Now applying the Newton's second law we have,

F= ma

F = (1587.57)(5.36)

F = 8516.36N

Therefore the approximate magnitude is 8516.36N

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SOMEBODY PLEASE HELP!! 20 PTS!!!
aliya0001 [1]

Answer:

1. Reflection

2. travel from one medium to another

3. Same waves to travel in opposite direction.  

Explanation:

1. When a wave strikes a solid barrier, it bounces back in the same medium. This wave behavior of bouncing back is known as reflection. Its like a basketball hitting a backboard. The ball bounces back at the same angle as it was incident. ∠i = ∠r

2. For refraction to occur in a wave, the wave must travel from one medium to another. When light travels from through mediums of different optical densities, it bends. The wave bends away normal when it enters from denser medium to rarer medium. The wave bends towards the normal when it enters from rarer to denser medium. The angle of refraction and angle of incidence are related by Snell's law.

\frac{sin(i)}{sin(r)} = \frac{\mu_2}{\mu_1}

3. The formation of standing wave requires two same waves to travel in the opposite direction and interfere. The incident wave and reflected wave when interfere, form standing waves. There waves are also resonances or harmonics. A standing wave oscillates at one place and does not transfers any energy.

3 0
3 years ago
Read 2 more answers
How do protons ever fuse together in the presence of the electromagnetic force? There is another force involved here called the
zepelin [54]

Answer:

The nuclei are moving fast with respect to one another

Explanation:

Protons are found in the nucleus together with the neutrons while the electrons normally revolve round it.

However the protons appears fused in a way when electromagnetic force is applied by the nuclei moving at a very fast speed. This fast speed helps to keep the supposed neutrons fused together.

7 0
3 years ago
A tree falls in a forest. How many years must pass before the 14C activity in 1.03 g of the tree's carbon drops to 1.02 decay pe
Illusion [34]

Answer:

t = 5.59x10⁴ y

Explanation:

To calculate the time for the ¹⁴C drops to 1.02 decays/h, we need to use the next equation:

A_{t} = A_{0}\cdot e^{- \lambda t}    (1)

<em>where A_{t}: is the number of decays with time, A₀: is the initial activity, λ: is the decay constant and t: is the time.</em>

To find A₀ we can use the following equation:  

A_{0} = N_{0} \lambda   (2)

<em>where N₀: is the initial number of particles of ¹⁴C in the 1.03g of the trees carbon </em>

From equation (2), the N₀ of the ¹⁴C in the trees carbon can be calculated as follows:        

N_{0} = \frac{m_{T} \cdot N_{A} \cdot abundance}{m_{^{12}C}}

<em>where m_{T}: is the tree's carbon mass, N_{A}: is the Avogadro's number and m_{^{12}C}: is the ¹²C mass.  </em>

N_{0} = \frac{1.03g \cdot 6.022\cdot 10^{23} \cdot 1.3\cdot 10^{-12}}{12} = 6.72 \cdot 10^{10} atoms ^{14}C    

Similarly, from equation (2) λ is:

\lambda = \frac{Ln(2)}{t_{1/2}}

<em>where t 1/2: is the half-life of ¹⁴C= 5700 years </em>

\lambda = \frac{Ln(2)}{5700y} = 1.22 \cdot 10^{-4} y^{-1}

So, the initial activity A₀ is:  

A_{0} = 6.72 \cdot 10^{10} \cdot 1.22 \cdot 10^{-4} = 8.20 \cdot 10^{6} decays/y    

Finally, we can calculate the time from equation (1):

t = - \frac{Ln(A_{t}/A_{0})}{\lambda} = - \frac {Ln(\frac{1.02decays \cdot 24h \cdot 365d}{1h\cdot 1d \cdot 1y \cdot 8.20 \cdot 10^{6} decays/y})}{1.22 \cdot 10^{-4} y^{-1}} = 5.59 \cdot 10^{4} y              

I hope it helps you!

4 0
3 years ago
Two trains are headed towards each other on the same track unbeknownst to the engineers. One departs San Francisco. Its average
aalyn [17]

Answer:

7,166 hrs =430  minutes

Explanation:

Since both train are on the same track, going one towards the other, the relative speed is the addition of both, then the time they need to meet, and consistently crash, is the time that (65mph + 55 mph)=120mph need to travel the total distance of 860 miles, of course in this case one part is traveled by the first train and the rest by the other. Then to find the time we use a three rule

1 h --->120mi

X ---->860mi, then X=(860 mi* 1h)/120 mi = 43/6 hrs= 7,16666 hrs, turning this into minutes need that we notice 1h=60min, then 43/6 hrs *60 min/hrs = 430 minutes.

7 0
3 years ago
Newton's laws of motion are true on earth and space.
frez [133]

Answer:

False

Explanation:

It is a common misunderstanding that objects in space have no weight. If that were true, they would just float away from the Earth, the Sun and the other planets. Objects in low Earth orbit experience about 90% of the weight that they feel on the surface of the Earth.

8 0
2 years ago
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