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Angelina_Jolie [31]
3 years ago
6

Which source is considered a primary source of scientific information? an original research article in a scientific journal a re

port about a new scientific discovery in the newspaper a book that compiles important new research findings a public lecture at a museum given by the scientist who did the research
Physics
2 answers:
Nitella [24]3 years ago
6 0
The primary source would be the original article published in a scientific journal. All other choices would be based on information from the original article.

Newspapers would only pick up the information from the journal itself, or from the authors. Books follow after the original article, after it has gained momentum among the research community. The public lecture at a museum would be based on work from the journal article.
laila [671]3 years ago
5 0

The primary source would be the original article published in a scientific journal.

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What properties of the wave define why it is found within this area of the spectrum?
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Answer:

Explanation:

Speed and medium are properties of a wave which is in common within an area of the spectrum of visible light. i.e;

Their medium of propagation

They both travel at the same speed ( speed of light )

The properties mentioned above are properties that define that wave is found within an area spectrum for visible light.

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Solar winds have an influence all the way to about 160 AU from the Sun. About how many kilometers is that?
Mumz [18]

Answer: A. 24,000,000,000 km

Explanation: An Astronomical Unit  commonly abbreviated as AU is the average distance between Earth and the Sun and is about 150 million kilometers.

Astronomical unit is mainly used to measure distances within our solar system.

1 AU is equal to  150\times 10^6 km

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4 0
3 years ago
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A photographer in a helicopter ascending vertically at a constant rate of accidentally drops a camera out the window when the he
maksim [4K]

Answer:

The time it takes for the camera to reach the ground is 5 s.

Explanation:

To solve this problem, we will use the free fall cinematic equation.

Since the helicopter ascends with constant speed, the camera falls to the ground only by the effect of gravity on it.

The speed at which the helicopter ascends is not specified in the statement, but according to a similar problem, we will use 12.5 \frac{m}{s}.

First, we must calculate the time and the maximum height at which the camera arrives after leaving the helicopter.

To calculate the maximum height to which it arrives, we will use the formula of vertical shot (since the camera leaves the helicopter with a speed upwards of 12,5 \frac{m}{s}).

V_{f} ^{2}=V_{0} ^{2} - 2 * g * h

Where:

V_{f}: final speed at maximum height.

V_{0}: initial speed when it falls from the helicopter.

g: gravity taken at 9.8 \frac{m}{s^{2} }

h: height reached from 60 m when leaving the helicopter

as V_{f}=0

0=(12,5\frac{m}{s}) ^{2} - 2 * 9,8\frac{m}{s^{2} } * h

clear h:

h=(12,5 \frac{m}{s^{2} } )^{2} / (2 * 9,8 \frac{m}{s^{2} })

h=7,97 m

Then we must calculate the time it takes to reach its maximum height:

V_{f}=V_{0} - g * t

t: time it takes to arrive from the moment it leaves the helicopter at its maximum height.

as V_{f}=0

0=12.5 \frac{m}{s} - 9.8 \frac{m}{s^{2} } * t

clearing t

t=12.5 \frac{m}{s} / 9.8 \frac{m}{s^{2} }

t=1.27 s.

Now we can calculate the time it takes to fall from the maximum height of 67.97 m.

The equation we will use is Y=v_{0}*t+(\frac{g*t^{2} }{2} )

where:

t: time it takes for the camera to fall.

Y: height from where the camera falls concerning the ground.

v_{0}: initial speed of the camera at the time of starting the fall.

g: acceleration of gravity, estimated at 9.8 \frac{m}{s^{2} }

Step 1: As the helicopter ascends with constant speed, the initial speed of the camera at the moment of falling is 0.

v_{0}=0

So the first term of our equation is nullified.

Step 2: To calculate the time it takes to fall, we clear "t" of the equation:

Y=\frac{(g*t^{2})}{2}

Y*2=(g*t^{2})

\frac{Y*2}{g}=t^{2}

\sqrt{\frac{Y*2}{g} }=t

Step 3: I replace the values with the incognites and get "t".

t=\sqrt{\frac{67,97m*2}{9,8\frac{m}{s^{2} } } }

t=3,73 s

The total time it takes for the camera to fall from the moment it leaves the helicopter is the sum of the time it takes to reach the maximum point of height and the time it takes to fall to the ground from that height.

t= 1,27 s + 3,73 s = 5 s

Have a nice day!

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