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2 years ago

Imporance of mixture in our daily life

1 answer:

4 0

Answer:A mixture is a mechanical combination of several elements or compounds. Mixtures are used in cooking, chemical manufacturing, and a lot of other processes. A good mixture with the materials evenly distributed facilitates a good after mixture process. That might be a chemical reaction or a great cake. One mixture that we see the results of a lot is the mixture of water, gravel, and Portland cement that, after a good mix, becomes concrete. Other mixtures might include the various plastics and epoxies that require two or more parts to become a finished product. There are so many possible mixtures out there I’d suggest chemical engineering books , chemistry books in general, cook books, books on construction processes, and many other possible sources of mixtures and the results of using them.

Explanation:

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If an acid has a ka=1.6x10^-10, what is the acidity of the solution?

LUCKY_DIMON [66]

The information given in the question is not enough to determine the acidity of the solution. This is because, acidity can only be found with the equation: pH = -log [H+].
In order to determine the acidity of the solution, the half titration point value is needed, this will make it possible to determine the value of H30+. If the half point titration value is known, then Ka will be equivalent to pH and the value will be evaluated using the equation: - log (1.6 * 10^-10).

5 0

2 years ago

Calculate the amount of water required to prepare 500g of 2.5% solution of sugar.

Snowcat [4.5K]

(i) We start by calculating the mass of sugar in the solution:

mass of sugar = concentration × solution mass

mass of sugar = 2.5/100 × 500 = 12.5 g

Then now we can calculate the amount of water:

solution mass = mass of sugar + mass of water

mass of water = solution mass - mass of sugar

mass of water = 500 - 12.5 = 487.5 g

(ii) We use the following reasoning:

If 500 g solution contains 12.5 g sugar

Then X g solution contains 75 g sugar

X=(500×75)/12.5 = 3000 g solution

Now to get the amount of solution in liters we use density (we assume that is equal to 1):

Density = mass / volume

Volume = mass / density

Volume = 3000 / 1 = 3000 liters of sugar solution

8 0

2 years ago

What mass of Ba3(PO4)2 is contained in 1575 mL of a 0.35 M solution of Ba3(PO4)2?

irina [24]

Answer:

= 331.81 g

Explanation:

Molarity is calculated by the formula;

Molarity = Moles/volume in liters

Therefore;

Moles = Molarity ×Volume in liters

= 0.35 M × 1.575 L

= 0.55125 Moles

But; Molar mass of Ba3(PO4)2 is 601.93 g/mol

Thus;

Mass = 0.55125 moles × 601.93 g/mol

3 0

2 years ago

Select the two elements isolated by the Curies.

Mkey [24]

Radium and polonium is the answer to this question. I hope I helped out!

5 0

2 years ago

Read 2 more answers

What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)

Genrish500 [490]

Answer:

34.28 L ( 1.5*22.4 L)

Explanation:

Calculation of the moles of aluminum as:-

Mass = 55 g

Molar mass of aluminum = 26.981539 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{55\ g}{26.981539\ g/mol}$

$Moles= 2.0384\ mol$

According to the reaction:-

$4Al+3O_2\rightarrow 2Al_2O_3$

4 moles of aluminum react with 3 moles of oxygen gas

1 mole of aluminum react with $\frac{3}{4}$ moles of oxygen gas

2.0384 moles of aluminum react with $\frac{3}{4}\times 2.0384$ moles of oxygen gas

Moles of oxygen gas = 1.5288 moles

At STP,

Pressure = 1 atm

Temperature = 273.15 K

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 1.5288 mol × 0.0821 L.atm/K.mol × 273.15 K

⇒V = 34.28 L ( 1.5*22.4 L)

7 0

2 years ago

Imporance of mixture in our daily life​

Imporance of mixture in our daily life