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Romashka-Z-Leto [24]
3 years ago
12

Plz help on number 4

Physics
1 answer:
ki77a [65]3 years ago
8 0
Forces on a Baseball. When a baseballis thrown or hit, the resulting motion of the ball is determined by Newton's laws of motion. ... Lift and drag are actually two components of a single aerodynamic force acting on the ball. Drag acts in a direction opposite to the motion, and lift acts perpendicular to the motion.
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Answer for a thanks
mariarad [96]
Well, if your question is how light affects plants,

then you would want to design an experiment that plays aruond with the amount of light a plant gets

thus the thing changing (or variable) would be amount of light
7 0
3 years ago
A battery is connected to a light bulb that has 3 of resistance . If there is 0.5 A of current flowing what is the voltage on th
Alenkasestr [34]

Answer:

1.5 V

Explanation:

E = IR = 0.5(3) = 1.5 V

8 0
3 years ago
What is it when you divide the total distance traveled by the total time
alexdok [17]

This is called average speed.Its really simple

4 0
3 years ago
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If the cart has potential energy of 5,000 J and kinetic energy of 2,750 J. How much mechanical energy does the cart have?
Dahasolnce [82]

Answer: 7750 J

Explanation:

Mechanical energy is potential energy added to kinetic energy.

5000 + 2750 J = 7750 J

6 0
3 years ago
A planet is discovered orbiting around a star in the galaxy Andromeda at four times the distance from the star as Earth is from
Dmitriy789 [7]

Answer:

Tp/Te = 2

Therefore, the orbital period of the planet is twice that of the earth's orbital period.

Explanation:

The orbital period of a planet around a star can be expressed mathematically as;

T = 2π√(r^3)/(Gm)

Where;

r = radius of orbit

G = gravitational constant

m = mass of the star

Given;

Let R represent radius of earth orbit and r the radius of planet orbit,

Let M represent the mass of sun and m the mass of the star.

r = 4R

m = 16M

For earth;

Te = 2π√(R^3)/(GM)

For planet;

Tp = 2π√(r^3)/(Gm)

Substituting the given values;

Tp = 2π√((4R)^3)/(16GM) = 2π√(64R^3)/(16GM)

Tp = 2π√(4R^3)/(GM)

Tp = 2 × 2π√(R^3)/(GM)

So,

Tp/Te = (2 × 2π√(R^3)/(GM))/( 2π√(R^3)/(GM))

Tp/Te = 2

Therefore, the orbital period of the planet is twice that of the earth's orbital period.

5 0
3 years ago
Read 2 more answers
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