This is the process of changing the shape of the eye lens to focus on near or distant objects.
Answer:
(a) The magnitude of the bird watcher's displacement is: 1.739 Km and (b) Average Velocity is: 0.863 Km/h.
Explanation:
To know the magnited of the bird watcher's displacement, we need to use cartesian coordinates. The distance that the bird watcher walked is the vector addition of all movement from the start point. So East = 1.4 - 3.26*Cos(78.6) = 0.756 Km and North = -1.63 + 3.26*Sen (78.6) = 1.566 Km when we have got result of both components axles, we use the pythagorean theorem to get the displacement that the bird watcher walked; R^{2}=x^{2}+y^{2} =\sqrt{0.756^{2}+(1.566)^{2}}=1.739(Km). Then we are going to calculate average velocity as: where delta_x is the displacement traveled by the bird watcher and delta_t is the total time using during the movement, so .
A becuz its at da it dont got no wa
Answer:
787528.7 J
Explanation:
Work done: This can be defined as the product of force and distance along the direction of force. The S.I unit of work is Joules (J).
From the question,
W = Tcos∅(d)............. Equation 1
Where W = work done, T = tension in the rope, ∅ = the angle of the rope to the horizontal, d = distance.
But,
d = v(t)..................... equation 2
Where v = velocity, t = time
Substitute equation 2 into equation 1
W = Tcos∅(vt)............. Equation 3
Given: T = 210 N, ∅ = 23°, v = 7 km/h = 1.94 m/s, t = 35 min = 2100 s
Substitute into equation 3
W = 210(cos23°)(1.94×2100)
W = 787528.7 J