<h3>X-Rays contradict to?</h3>
<h3>C. gamma </h3>
a type of penetrating electromagnetic radiation produced by the radioactive disintegration of atomic nuclei
Answer:
1.75 s
11.4 m
Explanation:
In the y direction:
Given:
Δy = -15.0 m
v₀ = 0 m/s
a = -9.8 m/s²
Find: t
Δy = v₀ t + ½ at²
-15.0 m = (0 m/s) t + ½ (-9.8 m/s²) t²
t = 1.75 s
In the x direction:
Given:
t = 1.75 s
v₀ = 6.50 m/s
a = 0 m/s²
Find: Δx
Δx = v₀ t + ½ at²
Δx = (6.50 m/s) (1.75 s) + ½ (0 m/s²) (1.75 s)²
Δx = 11.4 m
Answer:
<em>It takes 3 seconds to reach its high point</em>
Explanation:
<u>Projectile Motion</u>
In a projectile motion (or 2D motion), the object is launched with an initial angle θ and an initial velocity vo.
The components of the velocity are
The speed in the horizontal direction at any time t is:
The time taken to reach the maximum height is when vy=0, or:
We are given the y-component of the velocity, thus:
It takes 3 seconds to reach its high point
Answer:
149.8Hz
Explanation:
V=I.(XL).........{1}
where (XL) is inductive reactance
(XL) =2πfL......... {2}
V= 41.5, l= 4.5, L= 9.8* 10^-³
take π to be 3.14
(XL) = V/I
= 41.5/4.5
= 9.22
f = (XL) /2πL
= 9.22* 10^³/6.28* 9.8
=149.8
For this problem, we use the conservation of momentum as a solution. Since momentum is mass times velocity, then,
m₁v₁ + m₂v₂ = m₁v₁' + m₂v₂'
where
v₁ and v₂ are initial velocities of cart A and B, respectively
v₁' and v₂' are final velocities of cart A and B, respectively
m₁ and m₂ are masses of cart A and B, respectively
(7 kg)(0 m/s) + (3 kg)(0 m/s) = (7 kg)(v₁') + (3 kg)(6 m/s)
Solving for v₁',
v₁' = -2.57 m/s
<em>Therefore, the speed of cart A is at 2.57 m/s at the direction opposite of cart B.</em>
