Answer:- molar mass of the unknown gas is 71.5 gram per mol.
Solution:- From Graham's law of effusion rates, the rate of effusion of a gas is inversely proportional to the square root of it's molar mass.
When we compare the effusion rates of two gases then the formula for Graham's law is:
In this formula, V stands for volume and M stands for molar mass
Rate is volume effused per unit time. Since, the volumes are same, the formula could be written as:
let's say in formula, subscript 1 is for hydrogen gas and 2 is for the unknown gas.
Molar mass of hydrogen is 2.02 grams per mol and the time taken to effuse it is 2.42 min. The time taken to effuse the unknown gas is 14.4 min and we are asked to calculate it's molar mass. let's plug in the values in the formula:
doing squares to both sides:
So, the molar mass of the unknown gas is 71.5 grams per mol.
Rate = k[A] = first order reaction
<h3>Further explanation</h3>
Given
Rate law
Required
A first-order reaction
Solution
The rate law : equation for the rate of chemical reaction
For reaction
aA + bB ⇒ C
The rate : r = k[A]ᵃ[B]ᵇ
The sum of exponents(a+b) is the reaction order
From the choice :
a. a+b = 2, second order reaction
b. a+b = 3, third order reaction
c. a+b = 4, fourth order reaction
d a+0 = 1, first order reaction
Q: Which type of severe weather is related to high-pressure systems
A: A high pressure system is a whirling mass of cool, dry air that generally brings fair weather and light winds. When viewed from above, winds spiral out of a high-pressure center in a clockwise rotation in the Northern Hemisphere. These bring sunny skies. A high pressure system is represented as a big, blue H.
If you take this answer into consideration knowing the weathers, you will get your answer