Answer:
-35 m/s
Explanation:
Momentum is conserved.
Momentum before firing = momentum after firing
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
Before the bullet is fired, the bullet and rifle have no velocity, so u₁ and u₂ are 0.
0 = m₁v₁ + m₂v₂
Given m₁ = 0.7 kg, v₁ = 350 m/s, and m₂ = 7 kg:
0 = (0.7 kg) (350 m/s) + (7 kg) v
v = -35 m/s
The rifle recoils at 35 m/s in the opposite direction.
Answer:
The final velocity of the car is 2.02 m/s
Explanation:
Hi there!
The kinetic energy of the car as it runs along the first flat horizontal segment can be calculated using the following equation:
KE = 1/2 · m · v²
Where:
KE = kinetic energy
m = mass
v = velocity
Then, the initial kinetic energy will be:
KE = 1/2 · 0.100 kg · (2.77 m/s)²
KE = 0.384 J
When the car gains altitude, it gains potential energy. The amount of gained potential energy will be equal to the loss of kinetic energy. So let´s calculate the potential energy of the car as it reaches the top:
PE = m · g · h
Where:
PE = potential energy.
m = mass
g = acceleration due to gravity.
h = height.
PE = 0.100 kg · 9.8 m/s² · 0.184 m
PE = 0.180 J
Then, the final kinetic energy will be (0.384 J - 0.180 J) 0.204 J
Using the equation of kinetice energy, we can obtain the velocity of the car:
KE = 1/2 · m · v²
0.204 J = 1/2 · 0.100 kg · v²
2 · 0.204 J / 0.100 kg = v²
v = 2.02 m/s
The final velocity of the car is 2.02 m/s
Answer:
they can have the momentum if only they are been divided by another number to see the difference
It is because change in the Mass of the object balances the change in the Volume of the object equally...........
Answer:
The answer is 1.63 x 10 -7 N
Explanation:
