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Verdich [7]
3 years ago
6

An iv curve is generated for two ohmic devices, one is a good conductor and the other is a good insulator. which one will have a

lower slope?
Physics
1 answer:
allochka39001 [22]3 years ago
5 0

As per the question there are two ohmic devices.

The first ohmic device is a good conductor and the second one is a good insulator.

As per Ohm's law the current flowing through a conductor is directly proportional to the potential difference maintained across the two ends of a conductor at constant temperature and pressure. If V is the potential and I is the current flow through these Ohmic devices,then mathematically it can be written as-

                                                      V∝ I   [ at constant temperature and pressure]

                                                   ⇒V= IR

Here R is the proportionality constant called resistance of the material.

 Hence the resistance R  is calculated as -

                                                         R=\frac{V}{I}

Now a graph is plotted taking potential  V on X-axis and current I along Y- axis.

The graph will be a straight line  for conductor and will be a curve depending on the type of insulator.

The slope of this graph will give  the resistance of the material.

An insulator is a substance through which current flow is very low as its resistance is very high.Hence the slope of the V-I curve is very large.

A conductor is that substance through which current is flown easily as  the resistance of conductor is very low.Hence the slope of V-I curve is smaller,

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4 0
3 years ago
Calculate the acceleration of a 7,000 kg, single-engine airplane just before takeoff when the thrust of its
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3 0
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The low areas created as a sound wave propagates are called rarefactions
qwelly [4]

The answer is; pressure

The sound is a longitudinal wave meaning the particles vibrate parallel to the direction of the wave. Sound waves, therefore, produce compression (akin to the crest in a transverse wave) and rarefaction regions (akin to a trough in a transverse wave) as its energy is propagated in the medium.  


8 0
4 years ago
Read 2 more answers
A skateboarder shoots off a ramp with a velocity of 6.6 m/s, directed at an angle of 58 above the horizontal. The end of the ram
sweet-ann [11.9K]

Answer:

a) Maximum height reached above ground = 2.8 m

b) When he reaches maximum height he is 2 m far from end of the ramp.

Explanation:

a) We have equation of motion v²=u²+2as

   Considering vertical motion of skateboarder.  

   When he reaches maximum height,

          u = 6.6sin58 = 5.6 m/s

          a = -9.81 m/s²

          v = 0 m/s

  Substituting

         0²=5.6² + 2 x -9.81 x s

          s = 1.60 m

  Height above ground = 1.2 + 1.6 = 2.8 m

b) We have equation of motion v= u+at

   Considering vertical motion of skateboarder.  

   When he reaches maximum height,

          u = 6.6sin58 = 5.6 m/s

          a = -9.81 m/s²

          v = 0 m/s

  Substituting

         0= 5.6 - 9.81 x t

          t = 0.57s

  Now considering horizontal motion of skateboarder.  

  We have equation of motion s =ut + 0.5 at²

          u = 6.6cos58 = 3.50 m/s

          a = 0 m/s²

          t = 0.57  

  Substituting

         s =3.5 x 0.57 + 0.5 x 0 x 0.57²

         s = 2 m

  When he reaches maximum height he is 2 m far from end of the ramp.

8 0
4 years ago
An accelerometer has a damping ratio of 0.5 and a natural frequency of 18,000 Hz. It is used to sense the relative displacement
SOVA2 [1]

Answer:

A) i) Dynamic error ≈ 3.1%

   ii) phase shift ≈ -12°

B) 79971.89 rad/s

Explanation:

Given data :

Damping ratio = 0.5

natural frequency = 18,000 Hz

<u>a) Calculate the dynamic error and phase shift in accelerometer output at an impart vibration of 4500 Hz</u>

i) Dynamic error

This can be calculated using magnitude ratio formula attached below is the solution

dynamic error ≈ 3.1%

ii)  phase shift

This phase shift can be calculated using frequency dependent phase shift formula

phase shift ≈ -12°

<u>B) Determine resonance frequency </u>

  Wr = 2\pi ( 18000 \sqrt{0.5} ) = 79971.89 rad/s

C) The maximum magnitude ratio that the system can achieve

3 0
3 years ago
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