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430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
<h3>What is Molarity?</h3>
- The amount of a substance in a specific volume of solution is known as its molarity (M).
- The number of moles of a solute per liter of a solution is known as molarity.
<h3>Calculation of Required amount of AgCl</h3>
Remember that mol/L is the unit of molarity (M).
We can compute the necessary number of moles of solute by multiplying the concentration by the liters of solution, according to dimensional analysis.
0.75L×4.0M=3.0mol
Then, using the periodic table's molar mass for AgCl, convert from moles to grams:
3.0mol×143.321gmol=429.963g
The final step is to round to the correct significant figure, which in this case is two: 430g.
Hence, 430 g of AgCl would be needed to make a 4.0m solution with a volume of 0.75 L.
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Answer:
Explanation:
GIven that:
The activation energy = 250 kJ
k₁ = 0.380 /M
k₂ = ???
Initial temperature
1001 K
Final temperature
298 K
Applying the equation of Arrhenius theory.

where ;
R gas constant = 8.314 J/K/mol





/M .sec
Half life:
At 1001 K.


1.82368 secc
At 298 K:


Answer:
An Ionic Bond
Explanation:
Salt compounds are formed by the "donating" of electrons.

Formula mass of CaCO3 is
40 + 12 + 3-100amu....
100g CaCO3 = 1 mole..
50g of CaCO3 = 1÷ 100x 5 = 0.5mole...
<h3>Hence ,answer is 0.5mole...</h3>

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