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3 years ago

How would I find the answer?

Chemistry

1 answer:

ELEN [110]3 years ago

4 0

Answer:

Explanation:

The noble gas that is isoelectronic with Br⁻ is krypton.

This is because krypton is the closest noble gas to Br on the periodic table.

Electronic configuration of Bromine is;

2, 8, 18, 7

Br⁻ becomes; 2, 8, 18, 8

Krypton is; 2, 8, 18, 8

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From what is a nebula made

Naya [18.7K]

interstellar cloud of dust, hydrogen, helium and other ionized gases.

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4 years ago

If the number of moles of a gas initially contained in a 2.10 l vessel is doubled, what is the final volume of the gas in liters

Anon25 [30]

Avagadro's law gives the relationship between volume of gas and number of moles of the gas. When the temperature and pressure are constant, volume is directly proportional to number of moles of gas.
$\frac{V1}{n1} = \frac{V2}{n2}$
V -volume and n - number of moles of gas.
parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
initial number of moles n1 - N
n2 - 2N as the number of moles are doubled
V1 - initial volume - 2.10 L
V2 - final volume - V
substituting the values in the equation
$\frac{2.10L}{N} \frac{V}{2N}$
V = 4.20 L
final volume is 4.20 L

7 0

3 years ago

What is the concentration of the hydroxide ion? Given that the concentration of the hydronium ion is 2.3 X 10^-7 M

professor190 [17]

Answer:

4.35 * 10^-8 M

Explanation:

Since the concentration of the hydronium ion= 2.3 X 10^-7 M

And we know that;

[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+] = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

But [H3O^+] = 2.3 X 10^-7 M

[OH^-] = 1 * 10^-14/2.3 X 10^-7

[OH^-] = 4.35 * 10^-8 M

8 0

3 years ago

2. A solution is 0.01 M in Ba2+ and 0.01 M in Ca2+. Sodium sulfate is added to selectively precipitate one of the cations, while

lozanna [386]

Answer:

Explanation:

The solution contain 0.01 M concentration of Ba²⁺

0.01M concentration of Ca²⁺

Ksp ( solubility constant) for BaSO₄ = 1.07 × 10⁻¹⁰

Ksp for CaSO₄ = 7.10 × 10⁻⁵

(BaSO₄) = (Ba²⁺) (SO₄²⁻)

1.07 × 10⁻¹⁰ = 0.01 M (SO₄²⁻)

1.07 × 10⁻¹⁰ / 0.01 = ( SO₄²⁻)

1.07 × 10⁻⁸ M = ( SO₄²⁻)

so the minimum of concentration of concentration sulfate needed is 1.07 × 10⁻⁸ M

For CaSO₄

CaSO₄ = ( Ca²⁺) ( SO₄²⁻)

7.10 × 10⁻⁵ = 0.01 (SO₄²⁻)

(SO₄²⁻) = 7.10 × 10⁻⁵ / 0.01 = 7.10 × 10⁻³ M

so BaSO₄ will precipitate first since its cation (0.01 M Ba²⁺) required a less concentration of SO₄²⁻ (1.07 × 10⁻⁸ M ) compared to CaSO₄

b) The minimum concentration of SO₄²⁻ that will trigger the precipitation of the cation ( 0.01 M Ba²⁺) that precipitates first is 1.07 × 10⁻⁸ M

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4 years ago

In an undisturbed stack of rock layers, each containing fossils of once-living organisms, where would some evidence of the most

Gwar [14]

Answer:

A. At the top of the rock stack.

Explanation:

4 0

4 years ago