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Otrada [13]
3 years ago
9

Under certain conditions, the substance ammonium chloride can be broken down to form ammonia and hydrogen chloride. If 29.4 gram

s of ammonium chloride react to form 9.4 grams of ammonia, how many grams of hydrogen chloride must simultaneously be formed
Chemistry
1 answer:
lina2011 [118]3 years ago
5 0

Answer: 20.0 g of hydrogen chloride must simultaneously be formed

Explanation:

The balanced chemical reaction is :

NH_4Cl\rightarrow NH_3+HCl

According to the law of conservation of mass, mass can neither be created nor be destroyed. The mass on reactant side must be equal to the mass on product side.

Thus mass of reactants = mass of products

Given : mass of ammonium chloride = mass of reactants = 29.4 g

mass of ammonia = 9.4 g

mass of products = mass of ammonia + mass of hydrogen chloride

9.4 g +mass of hydrogen chloride = 29.4 g

mass of hydrogen chloride = 20.0 g

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A 250 ml solution of 2.0 M NaOH is diluted to 1.0 liter. What is the final concentration of the solution?
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Diluted concentration is 0.5M

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More easy:

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    Not feasible. ΔG°rxn = ΔG°f(product) > 0.

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    Feasible. ΔG°rxn = ΔG°f(product) < 0.

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