A. Solid turns into a gas
Answer:
1.4 * 10 ^-1 Ω
Explanation:
Hi,
For this question, we gotta use the formula
R = pL/A
p = The resistivity of your material at 20°C
L = length of the wire
A = cross-sectional area
The resistivity of tungsten is 5.60 * 10^-8 at 20°C
By plugging the values, we get:
R = (5.60 * 10^-8)(2.0)/(7.9*10^-7) = 1.4 * 10 ^-1 Ω
Answer:
1200 W
Explanation:
Power is given by the ratio between work done and time taken:
where W is the work done and t the time taken.
In this problem, W = 3600 J and t = 3.0 s. Therefore, the power in this exercise is
The cost of developing thermonuclear power with plasmabe defended because D. It can provide an inexpensive power source.
<h3>How did the
cost of developing t
hermonuclear power defended?</h3>
The cost of developing thermonuclear power defended becvause we can see in the paragraph how it was told that the generation of ths power can be donee through the understanding of the occurrence of plasmain nature,
It should be noted that this thermonuclear power with plasmabe posses the characteristics which make it to exist in the ionosphere, and it can be felt in the flames as well; as in the chemical and nuclearexplosions.
In conclusion the power can be seen as an inexpensive source power because the p[roduction of this power cn be found in most of the thing that can be found around us as discused above.
Therefore, option D is correct.
Read more about cost at:
brainly.com/question/25109150
#SPJ1
From the theory we know that:
c = λ / T
f = 1 / T
Where:
c = 3.
/ m (the speed of light)
λ is the wavelengh (in meters)
T is the period (in seconds)
f is the frequency (in Hz)
We were told that:
f = 7.30 . 
And we want to find out the value of λ.
c = λ / T
c = λ . 1/T
Swaping 1/T = f
c = λ . f
λ = c / f
λ = 3 . / 7.30 .
λ = 4.12 
m
Response: 4.12 m = 412 nm
:-)
