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2 years ago

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Which of the following increases the reaction rate? A. Adding a catalyst to the reaction mixture B. Increasing the size of solid

reactant particles C. Lowering the pressure of gaseous reactants D. Adding an inert gas to the reaction mixture

1 answer:

pickupchik [31]2 years ago

7 0

A. Adding a catalyst. A catalyst by definition is a compound that speeds up reaction rates.

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Sodium (Na) has 11 protons and 12 neutrons. What is its isotope notation?

DedPeter [7]

Answer:

Na ²³

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3 years ago

What statement correctly describes protons?

Ludmilka [50]

Answer:

A positively charged subatomic particle

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3 years ago

Use the solubility rules to determine if:

xenn [34]

<u>Answer:</u>

A reaction is said to occur if there is a formation of an insoluble solid or a precipitate(s) or a liquid (l) or a gas(g).

If both the reactants and products are in aqueous state, No reaction takes place.

$2 \mathrm{NaCl}(a q)+M g B r_{2}(a q)>M g C l_{2}(a q)+2 \mathrm{NaBr}(a q)(\mathrm{NO} \text { REACTION })$

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(REACTION TAKES PLACE)

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5 0

2 years ago

The temperature of 15.71 grams of gold rises from 32°C to 1,064°C, and then the gold melts completely. If gold’s specific heat i

antoniya [11.8K]

Answer:Total energy gained by 15.71 g is 3090.6471 joules

Explanation:

Given:

Q = heat gained by the 15.71 gram mass of gold

$Q=mc\Delta T +m\Delta H_{fusion}$

$\Delta T=(T_{final}-T_{initial})=(1064^oC-32^oC)=1032^oC$

c = specific heat capacity of gold = 0.1291 $joules/gram^oC$

m = mass of gold =15.71 g

$Q=15.71 g\times 0.1291 joules/gram^oC (1032^oC) +15.71 g\times 63.5 Joules/gram$

Heat gained by gold = $2093.0621 Joules + 997.585 Joules$

=3090.6471 joules

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2 years ago

What property do atoms of these elements have that helps make the molecules polar

DENIUS [597]

You have not mention here about those elements but the general concept for this is the:
uneven distribution ------> polar
even distribution -------> non-polar

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2 years ago