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xeze [42]
3 years ago
12

Which of the following increases the reaction rate? A. Adding a catalyst to the reaction mixture B. Increasing the size of solid

reactant particles C. Lowering the pressure of gaseous reactants D. Adding an inert gas to the reaction mixture
Chemistry
1 answer:
pickupchik [31]3 years ago
7 0
A. Adding a catalyst. A catalyst by definition is a compound that speeds up reaction rates.
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A gas occupies 50.0mL at a standard temp. What volume would it occupy at 335 Celsius with
tino4ka555 [31]

Answer:

V₂ = 111.3 mL

Explanation:

Given data:

Initial volume of gas = 50.0 mL

Initial temperature = standard = 273.15 K

Final volume = ?

Final temperature = 335 °C (335+273.15 = 608.15 K)

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 50.0  mL ×608.15 K / 273.15 k

V₂ = 30407.5 mL.K / 273.15 K

V₂ = 111.3 mL

7 0
3 years ago
The problems explain what I need, I also need the work shown or explained at the least
PtichkaEL [24]

Answer:

Q1/0.83L

Q2/ 6.606L

Q3/ 3.27L

Explanation:

All the question Charles law for ideal gases

And his law up right there ☝️

3 0
3 years ago
The pOH of a solution is 10.75. What is the concentration of OH– ions in the solution?
Lubov Fominskaja [6]
The correct answer is 1.778 x 10^-11M. Hope this helps.
4 0
3 years ago
All + HgCl, --------> AICI,
Free_Kalibri [48]

Answer:

64.7g

Explanation:

The balanced chemical equation of this question is as follows;

AlI + HgCl2 → HgI + AlCl2

Based on the above equation, 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide).

Using mole = mass/molar mass to convert mass of HgI to moles.

Molar mass of HgI = 200.59 + 127

= 327.59g/mol

Mole = 138/327.59

= 0.42mol

- If 1 mole of AlI (aluminum monoiodide) reacts to produce 1 mole of HgI (mercury iodide)

- Then 0.42 mol of HgI will be produced by 0.42mol of AlI.

Using mole = mass/molar mass

Mass = mole × molar mass

Molar mass of AlI = 27 + 127

= 154g/mol

Mass of AlI = 0.42 × 154

= 64.7g of AlI

5 0
3 years ago
The process by which people walk
BigorU [14]
Walking is what i think you are talking about

6 0
3 years ago
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