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tiny-mole [99]
3 years ago
15

If a car travels 23.8 meters in 4.2 seconds, what is its speed?

Physics
1 answer:
Lena [83]3 years ago
5 0
Displacement = Initial Velocity * time + 0.5 * acceleration * time^2

Initial velocity * time = 0 since we assume that the car is launching from start without motion.

So, displacement = 0.5 * acceleration * time ^ 2

23.8 = 0.5 * acceleration * 4.2^2

23.8 = 0.5 * 17.64 * acceleration

23.8 = 8.82 * acceleration

23.8/8.82 = acceleration = 2.69 m/s^2

Final Velocity = initial velocity + acceleration * time

Final velocity = 0 + 2.69 * 4.2 = 11.3 m/s
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8 0
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Mamont248 [21]

Given :

Initial speed of car A is 15 m/s and initial speed of car B is zero.

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To Find :

What fraction of the initial kinetic energy is lost in the collision.

Solution :

Initial kinetic energy is :

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Now, fraction of initial kinetic energy loss is :

Loss = \dfrac{\dfrac{225m}{2}-\dfrac{100m}{2}}{\dfrac{100m}{2}}\\\\Loss = \dfrac{125}{100}\\\\Loss = 1.25

Therefore, fraction of initial kinetic energy loss in the collision is 1.25 .

6 0
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m_a_m_a [10]

Answer:

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Explanation:

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Answer:

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Answer:

Properties of matter

Explanation:

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