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tangare [24]
3 years ago
13

Determine the distribution of charges on the sphere if it is made of non-conducting plastic.

Physics
1 answer:
Elden [556K]3 years ago
7 0

Answer:

If the sphere is made of a non-conducting material, charges can´t distribute freely over its surface or volume. In non-conducting material bodies, charges can be transported from a molecule to another nearest to it. Therefore if you rub an object with a positive charge with this sphere made of non-conducting plastic, the object will rip some negative charges (electrons) of that zone of the sphere. Therefore that zone will get a superficial positive charge density, but the non-affected zone of the sphere will keep having a null charge density.

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This is true. Hope I helped!

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An 11.0 kg object traveling south with momentum of 50.0 kg-m/s collides and sticks to a 9.50 kg object traveling directly west w
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Lightning bolts can carry currents up to approximately 20 kA. We can model such a current as the equivalent of a very long, stra
GalinKa [24]

Answer:

how large a magnetic field would you experience = 8.16 x 10∧-4T

Explanation:

I = 20KA = 20,000A

r = 4.9 m

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With time running out in a game, Rachel runs towards the basket at a speed of 2.5 meters per second and from half-court, launche
finlep [7]

Answer:

Rachel(2.5,0)

ball(6.5,4.7)

b.R=10.15m/s, 27.57deg

Explanation:

The reference angle of Rachel is 00^{0} while the ball is at 36^{0}

resolving rachel's speed to the horizontal, we have

Ux=2.5cos0

Ux=2.5m/s

resolving rachel's speed to the vertical we have,

Uy=2.5sin0

Uy=0

for the ball

resolving the speed to its horizontal component

Ux=8cos36

Ux=6.5m/s

Uy=8sin36

Uy=4.7m/s

Rachel(2.5,0)

ball(6.5,4.7)

To get the resultant of their speed

Add the horizontal speed of rachel to that of the ball to get the total horizontal speed

Add the vertical speed of rachel and the ball to get the total vertical speed component

TUx=2.5+6.5=9M/S

TUy=0+4.7=4.7m/s

R=\sqrt{(TUx^2+TUy^2}

R=\sqrt{(9^2+4.7^2}

R=\sqrt{(103)}

R=10.15m/s

the direction

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4 0
3 years ago
Solenoid 2 has twice the diameter, twice the length, and twice as many turns as solenoid 1. How does the field B2 at the center
klemol [59]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The correct option is  option 3

Explanation:

From the question we are told that

   The diameter of solenoid 1 is  d_1

   The length of solenoid 1 is   L_1

    The  number of turns of solenoid is  N_1

   The diameter of solenoid 2 is  d_2 = 2d_1

   The length of solenoid 2 is   L_2 = 2L_1

    The  number of turns of solenoid  2 is    N_2 = 2 N_1

Generally the magnetic in a solenoid is mathematically represented as

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From this equation we see that

     B  \ \alpha \  \frac{N}{L}

     B   =  C   \frac{N}{L}

Here C stands for constant

=>   C =  \frac{B *  \frac{L}{N}

=>    \frac{B_1 *  \frac{L_1}{N_1}   = \frac{B_2 *  \frac{L_2}{N_2}

=>  \frac{B_1}{B_2 }  =  \frac{N_1 L _2}{ N_2L_1}

=>   \frac{B_1}{B_2 }  =  \frac{N_1 * (2 L_1)}{ (2 N_2)L_1}

=>   \frac{B_1}{B_2 }  =  1

=>   B_2 = B_1

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