Answer:
6370 J
Explanation:
By the law of energy conservation, the work done by the student would be the change in potential enegy from 1st floor to 3rd floor, or a change of 13 m
![W = E_p = mgh](https://tex.z-dn.net/?f=W%20%3D%20E_p%20%3D%20mgh%20)
where m = 50kg is the mass of the student, g = 9.8 m/s2 is the gravitational constant and h = 13 m is the height difference
![W = 50*9.8*13 = 6370 J](https://tex.z-dn.net/?f=W%20%3D%2050%2A9.8%2A13%20%3D%206370%20J)
Answer:
D. the masses of the objects and the distance between them
Explanation:
Gravitation is a force, a force doesn't care about the shape or density of objects, only about their masses... and distances.
And you can get it using the following equation:
![f = \frac{Gm_{1}m_{2} }{d^{2} }](https://tex.z-dn.net/?f=f%20%3D%20%5Cfrac%7BGm_%7B1%7Dm_%7B2%7D%20%7D%7Bd%5E%7B2%7D%20%7D)
Where :
G is the universal gravitational constant
: G = 6.6726 x 10-11N-m2/kg2
m represent the mass of each of the two objects
d is the distance between the centers of the objects.
Answer:
<em>D.) state of matter</em>
Explanation:
it can undergo chemical but not nuclear.
Answer: It's hard to say without characterizing the collision. But it will be either A if the collision is totally in-elastic, or B if the collision is totally elastic. It could be anywhere in between for partially elastic collisions.
Explanation:
momentum is conserved, so initial system momentum will be left to right.
The velocity of the center of mass is 50(5) / 550 = 0.4545... m/s
In an elastic collision, the lead ball will move off at twice that speed or 0.91 m/s to the right.
The steel ball will bounce back and move away at 0.91 - 5 = -4.1 m/s . The negative sign indicates the steel ball has reversed course and has negative momentum
In a totally in-elastic collision, both balls would move to the right at 0.45 m/s. The steel ball will still have positive momentum.