Answer:
Using the equation of continuity:
A
1
v
1
=
A
2
v
2
0.08
(
10
)
=
A
2
(
225
)
A
2
=
3.55
×
10
−
3
m
2
Q
2
=
A
2
v
2
Q
2
=
3.55
×
10
−
3
×
225
Q
2
=
0.798
m
3
/
s
Explanation:
Steady Flow Energy Equation:
The steady flow energy equation is a representation of the first law of thermodynamics. It is the conservation of energy law for an open system. A nozzle is an open system in the context of thermodynamics. It is used to produce a high velocity by reducing its pressure.
The steady flow energy equation can be given by the following formula:
h
1
+
1
2
v
2
1
+
g
z
1
+
q
=
h
2
+
1
2
v
2
2
+
g
z
2
+
w
where 'h' is enthalpy, 'v' is velocity, 'z' is height, 'q' is the heat and 'w' is work.
h
=
C
p
d
T
Answer and Explanation:
Given:
initial temp,
T
1
=
400
0
C
initial Pressure,
p
1
=
800
k
P
a
Initial Velocity,
v
1
=
10
m
/
s
Final temp,
T
2
=
300
0
C
Final Pressure,
p
2
=
200
k
P
a
Rate of heat loss, Q = 25 KW
Inlet Area,
A
1
=
800
c
m
2
As per the steady flow energy equation:
h
1
+
1
2
v
2
1
+
g
z
1
+
q
=
h
2
+
1
2
v
2
2
+
g
z
2
+
w
Since, there is external work, w= 0. Also, consider there is a negligible change in KE.
h
1
+
1
2
v
2
1
+
q
=
h
2
+
1
2
v
2
2
h
1
−
h
2
+
1
2
v
2
1
+
q
=
1
2
v
2
2
C
p
(
T
1
−
T
2
)
+
1
2
(
10
)
2
+
25000
=
1
2
v
2
2
2
(
400
−
300
)
+
50
+
25000
=
1
2
v
2
2
2
(
400
−
300
)
+
50
+
25000
=
1
2
v
2
2
25250
=
1
2
v
2
2
v
2
≈
225
which is the answer.
Using the equation of continuity:
A
1
v
1
=
A
2
v
2
0.08
(
10
)
=
A
2
(
225
)
A
2
=
3.55
×
10
−
3
m
2
Now, volume flow rate,
Q
2
=
A
2
v
2
Q
2
=
3.55
×
10
−
3
×
225
Q
2
=
0.798
m
3
/
s
Answer:
Explanation:
Your car's owner's manual will provide a maintenance schedule designed to keep your brakes in good condition. Following it is the easiest way to avoid expense repairs and the potential for catastrophic brake failure. But at the very least, you should have your brakes inspected every year.
Short ones are 4.5 inches but long ones can be up to 8 inches.
Answer:
Volume=2160 m^3
Depth=2160/A m
Explanation:
Detailed explanation of the answer is given in the attached files.
Answer:
-Differential equation: d²T/dx² = 0
-The boundary conditions are;
1) Heat flux at bottom;
-KAdT(0)/dx = ηq_e
2) Heat flux at top surface;
-KdT(L)/dx = h(T(L) - T(water))
Explanation:
To solve this question, let's work with the following assumptions that we are given;
- Heat transfer is steady and one dimensional
- Thermal conductivity is constant.
- No heat generation exists in the medium
- The top surface which is at x = L will be subjected to convection while the bottom surface which is at x = 0 will be subjected to uniform heat flux.
Will all those assumptions given, the differential equation can be expressed as; d²T/dx² = 0
Now the boundary conditions are;
1) Heat flux at bottom;
q(at x = 0) is;
-KAdT(0)/dx = ηq_e
2) Heat flux at top surface;
q(at x = L):
-KdT(L)/dx = h(T(L) - T(water))