a rubber band suspended from a hook first and stretched and then released. write the force exerting here and the effect of force
1 answer:
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Answer:
E = ρ ( R1²) / 2 ∈o R
Explanation:
Given data
two cylinders are parallel
distance = d
radial distance = R
d < (R2−R1)
to find out
Express answer in terms of the variables ρE, R1, R2, R3, d, R, and constants
solution
we have two parallel cylinders
so area is 2 R × l
and we apply here gauss law that is
EA = Q(enclosed) / ∈o ......1
so first we find Q(enclosed) = ρ Volume
Q(enclosed) = ρ ( R1² × l )
so put all value in equation 1
we get
EA = Q(enclosed) / ∈o
E(2 R × l) = ρ (
R1² × l ) / ∈o
so
E = ρ ( R1²) / 2 ∈o R