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3 years ago

6

Who theorized that electromagnetic radiation is emitted from a black hole due to quantum effects near the event horizon. Hint: A

famous scientist is named after this radiation who unfortunately passed away in March of last year. You will be missed :(

1 answer:

wolverine [178]3 years ago

6 0

Answer:

Stephen William Hawking

Explanation:

Stephen William Hawking was a popular theoretical physicist born on 8th January 1942.

He served as the professor of mathematics at the Cambridge university

He was director at the center for theoretical cosmology.

He has theorized that the black holes will emit radiations and the radiations is known by his name Hawking's radiation.

His book 'The Brief History of Time' appeared as one of the best seller according to the Sunday Times.

Hawking's was diagnosed for a rare disease named as motor neuron disease.

He received numerous awards and elected as the fellow of royal society.

He passed away on 14th March 2018.

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Rasek [7]

Answer:

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Explanation:

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3 years ago

It is said that a gas fills all the space available to it. Why then doesn't the atmosphere go off into space?

Alex777 [14]

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7 0

3 years ago

An airplane is flying in a horizontal circle at a speed of 480 km/h (). If its wings are tilted at angle =40° to the horizontal

german

Answer:

$R = 2162 m$

Explanation:

When wings of the airplane makes an angle of 40 degree with the horizontal so here we can say that force due to air is having two components

$F_y = mg$

$F_x = \frac{mv^2}{R}$

now we know that

$F_y = F cos40$

$F_x = F sin40$

also we know that

$v = 480 km/h$

$v = 133.3 m/s$

now plug in all data in above equations

$tan 40 = \frac{v^2}{Rg}$

$R = \frac{v^2}{g tan40}$

$R = \frac{133.3^2}{9.8 tan40}$

$R = 2162 m$

6 0

3 years ago

Under some circumstances, a star can collapse into an extremely dense object made mostly of neutrons and called a neutron star.

Andrews [41]

Answer:

The question is incomplete however this kind of questions about determinate the angular speed and taking a reference of days rotating the first star.

w=0.11312 rad/s

Explanation:

The situation is about a two star the question is incomplete, miss the time rotate one star so we assume the first star rotated once in 30 days so:

Angular momentum

$P_{m}=I*w$

The inertia

$I=\frac{3}{5}*m*r^2$

The momentum must be conserved so

$P_{m1}=P_{m2}$

$I_{1}*w_{1}=I_{2}*w_{2}$

$\frac{2}{5}*m*r_{1}^2*w_{1}=\frac{2}{5}*m*r_{2}^2*w_{2}$

notice don't have to know the mass or use the density however at the end can determinate

$w_{2}=\frac{r_{1}*w_{1}}{r_{2}}$

Time can determinate the frequency so determinate angular speed of the first star

$w_{1}=2\pi*f_{1}$

$t_{1}=30days*\frac{24hr}{1day}*\frac{60minute}{1hr}*\frac{60s}{1minute}=2592000s$

$f_{1}=\frac{1}{t_{1}}=\frac{1}{2592000}=3.858x10^-7Hz$

$w_{1}=2.424x10^{-6}\frac{rad}{s}$

$w_{2}=\frac{7.0x10^8m}{15x10^3m}*2592000$

$w_{2}=0.11312 rad/s$

4 0

3 years ago

The solid shaft with a 20 mm radius is used to transmit the torques applied to the gears. Determine the maximum torsional shear

AysviL [449]

Answer:

τ = (7.96 x 10⁴ m⁻³)T

This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.

Explanation:

The maximum allowable shear stress on the solid shaft can be given by the torsional formula as follows:

τ = Tc/J

where,

τ = Maximum Allowable Shear Stress = ?

T = Maximum Torque Applied to the Shaft

c = maximum distance from center to edge = radius in this case = 20 mm = 0.02 m

J = Polar Moment of inertia = πr⁴/2 = π(0.02 m)⁴/2 = 2.51 x 10⁻⁷ m⁴

Therefore,

τ = T(0.02 m)/(2.51 x 10⁻⁷ m⁴)

<u>τ = (7.96 x 10⁴ m⁻³)T</u>

<u>This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.</u>

3 0

3 years ago