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2 years ago

Why is it important to warm up your muscles before a workout?

Physics

2 answers:

ohaa [14]2 years ago

8 0

So you could grow and stay healthy

slava [35]2 years ago

7 0

Answer: So that you don't have a cramp

Explanation: Muscles can cramp up if not stretched becuase it keeps the muscles flexable and strong and to maintain the range of motion a person has.

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An airplane accelerates from a speed of 88m/s to a speed of 132 m/s during a 15 second time interval. How far did the airplane t

Gelneren [198K]

Answer:

$1650\:\mathrm{m}$

Explanation:

We can use the following kinematics equations to solve this problem:

$v_f=v_i+at,\\{v_f}^2={v_i}^2+2a\Delta x$ .

Using the first one to solve for acceleration:

$132=88+a(15),\\15a=44,\\a=\frac{44}{15}=2.9\bar{3}\:\mathrm{m/s^2}$ .

Now we can use the second equation to solve for the distance travelled by the airplane:

$132^2=88^2+2\cdot2.9\bar{3}\cdot \Delta x,\\\Delta x= \frac{9680}{2\cdot2.9\bar{3}},\\\Delta x =\fbox{$ 1650\:\mathrm{m}$}$ (three significant figures).

6 0

2 years ago

A very small object carrying -7 μC of charge is attracted to a large, well-anchored, positively charged object. How much kinetic

miss Akunina [59]

Answer:

ΔK.E = 14 nJ

Explanation:

Solution:

- The charge that moves under the influence of an Electric Field produced between a potential difference (V) stores electric potential energy U within that is converted to kinetic energy.

- We will use conservation of energy on the system that contains the charged particle with charge q loses its electric potential energy U as it moves towards positively charged object that converts into a gain in Kinetic energy of the charged particle ΔK.E:

ΔK.E = U

Where,

U = V*q

ΔK.E = V*q

ΔK.E = (7*10^-6)*(2*10^-3)

ΔK.E = 14 nJ

- The gain in kinetic energy is 14 nJ.

7 0

3 years ago

3. How do electric and magnetic forces act on different object?

zloy xaker [14]

The answer is C I believe

8 0

3 years ago

A curve of radius 166 m is banked at an angle of 11°. An 736-kg car negotiates the curve at 81 km/h without skidding. Neglect th

lianna [129]

Answer:

$F_n = 7509.33\ N$

Explanation:

given,

radius of curve = 166 m

angle of the banked road = 11°

mass of car = 736 Kg

speed of the curve = 81 km/h

= 81 x 0.278 = 22.52 m/s

normal force acting on the tires

on tire there will be two force acting on it

first one will be force acting due to weight and the other force acting on the tire is due to centripetal force.

$F_n = m g cos \theta+ \dfrac{mv^2}{r} sin \theta$

$F_n = 736 \times 9.8 \times cos 11^0+\dfrac{736 \times 22.52^2}{166} sin 11^0$

$F_n = 7080.28+429.047$

$F_n = 7509.33\ N$

6 0

2 years ago

A hockey puck sliding on smooth ice at 4 m/s comes to a 1-m-high hill. Will it make it to the top of the hill?

solniwko [45]

Answer:

No it will not make to the top of the hill

Explanation:

From the question we are told that

The velocity is $v = 4 \ m/s$

The height of the hill is $h = 1 \ m$

Generally from the law of energy conservation we have that

The kinetic energy of the pluck at the level position = The potential energy of the pluck at the maximum height the pluck can get to

$\frac{1}{2} * m * v^2 = m * g * h_{max}$

=> $\frac{1}{2} * v^2 = g * h_{max}$

=> $h_{max} = \frac{0.5 * v^2}{g}$

=> $h_{max} = 0.8163 \ m$

Given that the maximum height which the pluck can get to at this speed given in the question is less than the height of the hill then conclusion will be that the pluck will not make it to the top of the hill

3 0

2 years ago