Question

A big box of sausages (30 kg) is lifted from the ground to the top shelf of the freezer. If the box is lifted at a constant speed, a distance of 1.75 m, what work is done against gravity?

Answer 1

Answer:

Work done to lift the box is 515.03 J

Explanation:

By work energy theorem we know that work done by all forces is equal to change in kinetic energy

So we have

$W_g + W_{ex} = \Delta K$

so we have

$-mgh + W_{ex} = 0$

so we have

$W_{ex} = mgh$

$W_{ex} = 30(9.8)1.75$

$W_{ex} = 515.03 J$