Answer:
(A) 9.5 m/s
(B) 5.225 m
Explanation:
vertical height (h) = 4.7 m
horizontal distance (d) = 9.3 m
acceleration due to gravity (g) = 9.8 m/s^{2}
initial speed of the fish (u) = 0 m/s
(A) what is the pelicans initial speed ?
- lets first calculate the time it took the fish to fall
s = ut + 
since u = 0
s = 
t =
where a = acceleration due to gravity and s = vertical height
t =
= 0.98 s
- pelicans initial speed = speed of the fish
speed of the fish = distance / time = 9.3 / 0.98 = 9.5 m/s
initial speed of the pelican = 9.5 m/s
(B) If the pelican was traveling at the same speed but was only 1.5 m above the water, how far would the fish travel horizontally before hitting the water below?
vertical height = 1.5 m
pelican's speed = 9.5 m/s
- lets also calculate the time it will take the fish to fall
s = ut + 
since u = 0
s = 
t =
where a = acceleration due to gravity and s = vertical height
t =
= 0.55 s
distance traveled by the fish = speed x time = 9.5 x 0.55 = 5.225 m
Answer:
Option D
The frequency
Explanation:
The speed of wave is depedant only on the wavelength and frequency of waves since it is given by s=fw where s is the speed, f is frequency and w is the wavelength. Since the options given has only one factor, that is frequency, hence option D is correct. In case we had wavelength could be among the options, both would be correct.
The sound power the person generated is
.
<h3>Area of the sound wave</h3>
The area of the sound wave is calculated as follows;

<h3>Power generated</h3>
The sound power the person generated is calculated as follows;

Learn more about intensity of sound here: brainly.com/question/4431819
Answer:
0.031 W
Explanation:
The power used is equal to the rate of work done:

where
P is the power
W is the work done
t is the time taken to do the work W
In this problem, we have:
W = 900 J is the work done by the motor
t = 8 h is the time taken
We have to convert the time into SI units; keeping in mind that
1 hour = 3600 s
We have

And therefore, the power used is

The answer is wind forces and Earth’s rotation