Jasmine and her partner want to test to see if there is a relationship between how much of her solar panel is exposed to sunligh
t and how fast her solar car will move. She uses a piece of paper to cover the solar panel different amounts of her solar panel. The chart below shows the data she collected.
Which of the following is the best reason for Jasmine and her partner to take three (3) different trials for this experiment?
They had to fill out all of the lines on the chart.
They wanted at least 15 points to put on her graph.
Any one trial might have been done incorrectly.
The car didn’t work at first.
Which of the following is the best reason for Jasmine and her partner to take three (3) different trials for this experiment?
They had to fill out all of the lines on the chart.
They wanted at least 15 points to put on her graph.
Any one trial might have been done incorrectly.
The car didn’t work at first.
1 answer:
You might be interested in
This question is incomplete, the complete question;
The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.
Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb
Answer:
- the magnitude of force at point A is 79.1033 lb
- since FA < FA_max; Ladder WILL NOT slip
Explanation:
Given that;
∑'MA = 0
⇒ NB [Lsin∅] - W[L/2.cos∅] = 0
NB = W / 2tan∅ -------let this be equation 1
∑Fx = 0
⇒ FA - NB = 0
FA = NB
therefore from equation 1
FA = NB = W / 2tan∅
we substitute in our values
FA = NB = 76 / 2tan(60°) = 21.9393 lb
Now ∑Fy = 0
NA - W = 0
NA = W = 76 lb
Net force at A will be
FA' = √( NA² + FA²)
= √( (W)² + (W / 2tan∅)²)
we substitute in our values
FA' = √( (76)² + (21.9393)²)
= √( 5776 + 481.3328)
= √ 6257.3328
FA' = 79.1033 lb
Therefore the magnitude of force at point A is 79.1033 lb
Now maximum possible frictional force at A
FA_max = μ × NA
so, FA_max = 0.4 × 76
FA_max = 30.4 lb
So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.
Therefore since FA < FA_max; Ladder WILL NOT slip
