All categories

2 years ago

How was the modern understanding of the atom developed?

Chemistry

1 answer:

Zepler [3.9K]2 years ago

8 0

Answer:

The modern understanding of an atom was developed by the quantum theory

You might be interested in

Identify the true statements regarding α-1, 6 linkages in glycogen.A. The number of sites for enzymes action on a glycogen molec

kenny6666 [7]

Answer:

C. The reaction that forms α-1, 6 linkages is catalyzed by branching enzymes.

Explanation:

α-glucan branching enzyme which can also be called the Brancher enzyme or glycogen-branching enzyme is the enzyme responsible for the side chain reaction that attaches at carbon atom 6 of a glucose unit (an α-1,6-glycosidic bond).

This branching enzyme attaches a string of seven glucose units to the carbon at the C-6 position on the glucose unit, forming the α-1,6-glycosidic bond.

5 0

3 years ago

In this Punnett square, what is the probability of the offspring being a heterozygous purple flower

olya-2409 [2.1K]

Heterozygous means A capital P with a lowercase p. There are two purple flowers in the Punnett square with Pp out of 4 possible options. 2/4 is 1/2 which is 50%. So there is a 50% chance of a purple heterozygous flower.

8 0

2 years ago

If a frog has 26 chromosomes in its body cells, then it must have ______ cells in its gametes

miskamm [114]

Answer:

sxfdcghbjkml

Explanation:

4 0

2 years ago

How many number of moles are present in 200. g of sodium bicarbonate (NaHCO3)

nikdorinn [45]

You can solve this problem through dimensional analysis.

First, find the molar mass of NaHCO3.

Na = 22.99 g

H = 1.008 g

C = 12.01 g

O (3) = 16 (3) g

Now, add them all together, you end with with the molar mass of NaHCO3.

22.99 + 1.008 + 12.01 + 16(3) = 84.008 g NaHCO3. This number means that for every mole of NaHCO3, there is 84.008 g NaHCO3. In simpler terms, 1 mole NaHCO3 = 84.008 g NaHCO3.

After finding the molar mass of sodium bicarbonate, now you can use dimensional analysis to solve for the number of moles present in 200. g of sodium bicarbonate.

$200. g NaHCO_3 * \frac{1 mole NaHCO_3}{84.008 g NaHCO_3}$

Cross out the repeating units which are g NaHCO3, and the remaining unit is mole NaHCO3

200. * 1 = 200

200/ 84.008 = 2.38

Notice how there are only 3 sig figs in the answer. This is because the given problem only gave three sig figs.

Your final answer is 2.38 mol NaHCO3.

8 0

2 years ago

I need help plz this is driving me crazy

Elis [28]

A= 6
B= 2
C= 1
D= 5
E= 3
F= 4

4 0

2 years ago