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mixas84 [53]
3 years ago
5

A block oscillating up and down on a spring comes to the top of its path, where it is momentarily at rest. At the instant it is

at rest, what is the direction of the rate of change of its momentum?
Physics
1 answer:
True [87]3 years ago
7 0

Opposite to the direction of the velocity which led it to its current position.

Explanation:

The direction of momentum when a vertically oscillating block comes to the rest momentarily will be opposite to the direction of the velocity that it has just followed to reach reach its current position.

The direction of change in momentum at the bottom will be upwards and at the top will be downwards.

The change in momentum is mathematically defined as:

\Delta P=m.v_f-m.v_i

where:

m= mass of the block

v_f= final velocity of the block

v_i= initial velocity of the block

When the block comes to rest it is due to the result of continuously decreasing velocity.

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Consider a large 1.54 V carbon-zinc dry cell used in a physics lab to supply 2.15 A to a circuit. The internal resistance of the
andrew-mc [135]
<h2>Answer:</h2>

1.77V

<h2>Explanation:</h2>

The electromotive force voltage (E) in a cell, is related to the lost voltage (V_{L}) and the terminal voltage (V_{T}) as follows;

E = V_{T} - V_{L}

Where;

The lost voltage (V_{L}) is the product of the internal resistance (r) of the cell and current (I) in the cell. i.e

V_{L} =  I x r

<em>Substitute </em>V_{L}<em> =  I x r into equation (i) as follows;</em>

E = V_{T} - (I x r)           ----------------------(ii)

<em>According to the question;</em>

E = 1.54V

I = 2.15A

r = 0.105Ω

<em>Substitute these values into equation(ii) as follows;</em>

1.54 = V_{T} - (2.15 x 0.105)

1.54 = V_{T} - (0.22575)

1.54 = V_{T} - 0.22575

<em>Solve for </em>V_{T}<em>;</em>

V_{T} = 1.54 + 0.22575

V_{T} = 1.54 + 0.22575

V_{T} = 1.77V

Therefore, the terminal voltage of the cell is 1.77V

8 0
3 years ago
A projectile is launched horizontally from a height of 8.0 m. The projectile travels 6.5 m before hitting the ground.
spayn [35]

Answer:

5.09 m/s

Explanation:

Use the height to find the time it takes to land:

y = y₀ + v₀ᵧ t + ½ gt²

0 = 8.0 m + (0 m/s) t + ½ (-9.8 m/s²) t²

t = 1.28 s

Now use the horizontal distance to find the initial velocity.

x = x₀ + v₀ₓ t + ½ at²

6.5 m = 0 m + v₀ (1.28 s) + ½ (0 m/s²) (1.28 s)²

v₀ = 5.09 m/s

7 0
3 years ago
A student has a small piece of steel.
Simora [160]

Answer:

There are different ways to investigate density. In this required practical activity, it is important to:

record the mass accurately

measure and observe the mass and the volume of the different objects

use appropriate apparatus and methods to measure volume and mass and use that to investigate density

Explanation:

5 0
3 years ago
A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent
azamat

The wavelengths of the constituent travelling waves CANNOT be 400 cm.

The given parameters:

  • <em>Length of the string, L = 100 cm</em>

<em />

The wavelengths of the constituent travelling waves is calculated as follows;

L = \frac{n \lambda}{2} \\\\n\lambda = 2L\\\\\lambda = \frac{2L}{n}

for first mode: n = 1

\lambda = \frac{2\times 100 \ cm}{1} \\\\\lambda = 200 \ cm

for second mode: n = 2

\lambda = \frac{2L}{2} = L = 100 \ cm

For the third mode: n = 3

\lambda = \frac{2L}{3} \\\\\lambda = \frac{2 \times 100}{3} = 67 \ cm

For fourth mode: n = 4

\lambda = \frac{2L}{4} \\\\\lambda = \frac{2 \times 100}{4} = 50  \ cm

Thus, we can conclude that, the wavelengths of the constituent travelling waves CANNOT be 400 cm.

The complete question is below:

A string of length 100 cm is held fixed at both ends and vibrates in a standing wave pattern. The wavelengths of the constituent travelling waves CANNOT be:

A. 400 cm

B. 200 cm

C. 100 cm

D. 67 cm

E. 50 cm

Learn more about wavelengths of travelling waves here: brainly.com/question/19249186

5 0
2 years ago
Jeff is a landscaping contractor and lifts a rock weighing 600 pounds by wedging a board under the rock. Jeff weighs 150 pounds
jonny [76]

Answer: 4

The mechanical advantage is the ratio of the force exerted  by the object to the force applied to do work on it.

Here, Jeff tried to lift a rock weighing 600 pounds by wedging board under the rock. Jeff who weighs 150 pounds uses all his weight to exert force on lever and lift rock.

Mechanical advantage, M.A.=\frac{weight\hspace{1mm}of\hspace{1 mm}rock}{weight\hspace{1mm}of\hspace{1 mm}Jeff}=\frac{600 pounds}{150 pounds}=4.

Therefore, the mechanical advantage that lever provided to Jeff in lifting rock is 4.

6 0
2 years ago
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