A block oscillating up and down on a spring comes to the top of its path, where it is momentarily at rest. At the instant it is
1 answer:
Opposite to the direction of the velocity which led it to its current position.
Explanation:
The direction of momentum when a vertically oscillating block comes to the rest momentarily will be opposite to the direction of the velocity that it has just followed to reach reach its current position.
The direction of change in momentum at the bottom will be upwards and at the top will be downwards.
The change in momentum is mathematically defined as:
where:
mass of the block
final velocity of the block
initial velocity of the block
When the block comes to rest it is due to the result of continuously decreasing velocity.
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Answer:
R=100 Ohm, V=11.97 volts and I=0.12 amperes
R=10 Ohm, V=10.25 volts and I=1.20 amperes
R=2 Ohm, V=6.26 volts
Explanation:
The potential difference (voltage) of a battery with internal resistance is:
(1)
with the electromotive force (the voltage the batteries say to has) , I the current and r the internal resistance. By Ohm's law the current that passes through the resistor is:
(2)
using (2) on (1):
solving for V:
(3)
R=100 Ohm
R=10 Ohm
R=2 Ohm
Because we have now the values of I on the circuit (is the same through all the components because is a series circuit)
We use back substitution on (1) to find the current:
R=100 Ohm
R=10 Ohm