I believe u do not need the radius because we are looking for the angular displacement and not the linear analog. So this is simply
(6 rad/s)(2.5s)= 15 rad if i am correct
Answer:
My favourite university is the University of Machigan.
Explanation:
The motto boldly reads 'Artes, Scientia, Vertia' at University of Machigan which means Arts, Knowledge, and Truth in Latin. Since I was in high school, I always wanted to acquire education/college degree from a university that lived up to its motto. I had a great interest in Social Science and Humanities and always wanted to make a career out of it. The University of Machigan first came across to me while I was reading a monthly magazine at our school library. I read an article called 'Constructing the System: Government and Stakeholders' written by a college student from the University of Machigan. It had interesting developments and insights which really interested me. In fact, it included a very crucial piece of information which was similar to my own political principles.
I did some further research on papers and programs offered at University of Machigan and I felt that it was just the right university for me. I read numerous papers and articles from different departments which were all very academic oriented. Moreover, I started updating myself with the admission criteria at University of Machigan every year and is currently working really hard to achieve admissions there.
I'm still few months away from graduating high school but I can already feel the excitement to go there. I have faith in my academic records and potentials that I would make it there. I'm planning to take up 'Government and Politics' program since that is what I'm most interested at. I hope I would learn and acquire the best knowledge and opportunity from one of the best universities in US or I must say, my favourite university.
Answer:
130m/s^2 and 1.22s
Explanation:
From V = u+at
Where V, u, a, and t are the final velocity, initial velocity, acceleration and time respectively.
v = 6.75m/s
u = 3.5m/s
t = 0.250secs
a = ?
V = u+at
6.75= 3.5+a(0.250)
6.75-3.5 = 0.250a
3.25=0.250a
Divide both sides by 0.250
3.25/0.250= 0.250a/0.250
a = 130m/s^2
The acceleration of the will be 130 meter per second
Question 2
Speed = distance/time
Given that speed= 4.25m/s
Distance = 5.2m and time = ?
4.25m/s = 5.2m/t
Cross multiply
4.25×t = 5.2
Make t the subject by dividing both sides by 4.25
4.25t/4.25 = 5.2/4.25
t = 1.22s
Hence the time taken will be 1.22 seconds
Answer:
The velocity of the second car when it passes the first car is 40 m/s
Explanation:
The position and velocity of the cars is given by the following equations:
x = x0 + v0 · t + 1/2 · a · t²
v = v0 + a · t
Where:
x = position at time t
x0 = initial position
v0 = initial velocity
t = time
a = acceleration
v = velocity at time t
If the velocity is constant, then a = 0 and x = x0 + v · t
When the second car passes the first car, the position of both cars is the same:
x first car = x second car
x0 + v · t = x0 + v0 · t + 1/2 · a · t² (x0 = 0 and v0 = 0)
v · t = 1/2 · a · t²
2 · v /a = t
2 · 20 m/s / 2.0 m/s² = t
t = 20 s
Using the equation of velocity, we can calculate the velocity of the second car at t = 20 s
v = v0 + a · t
v = 0 m/s + 2.0 m/s² · 20 s = 40 m/s
The velocity of the second car when it passes the first car is 40 m/s
PEG = 0.8*KE.
M*g*h = 0.8 *(0.5*M*v^2) M, h, and v are the vaulter's mass, height, and speed, respectively.
g*h = 0.8*0.5*v^2 Divide both sides by M (the mass).
g*h = 0.4*v^2
(9.81 m/s^2)*h = 0.4*(7 m/s)^2. Note that m and s denote meter and second, respectively.
h = 0.4*(7 m/s)^2 /(9.81 m/s^2) Divide both sides by 9.81 m/s^2. Also, note that m is NOT mass here.
= 0.4*(49 m^2/s^2)/(9.81 m/s^2)
= 0.4*49 m/9.81
Answer = 1.99796 meters