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anzhelika [568]
3 years ago
11

You are stuck far away from your house. You decide to walk to your house which is a distance of 32 blocks. How many minutes will

it take if you walk one mile in 20 minutes? 9 blocks equal 1 mile.
Chemistry
1 answer:
trasher [3.6K]3 years ago
3 0

Answer:

It will take 71.1 minutes to get home. I hope this helps!

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C because it is maximumly contracted
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The pressure of a gas is caused by
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The rapid motion and collisions of molecules with the walls of the container causes pressure.

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You have a 150mL sample of an aqueous solution at 25C. It contains 15.2mg of an unknown nonelectrolyte compound. If the solution
Serga [27]

The molar mass of the compound:

If the solution has an osmotic pressure of 8.44 torr, then the molar mass of the unknown non-electrolyte is 223.14 g.

What is osmosis?

  • Osmosis is defined as the flow of solvent molecules through semi-permeable membrane.
  • Osmotic pressure is the pressure applied to stop the flow of solvent molecules.
  • It is a colligative property that means osmotic pressure depends on the number of solute particles .

Therefore,

πV=inRT  ( for electrolytes)

Where,   π= Osmotic pressure

i = Van 't Hoff factor

n= moles

R= Gaseous constant = 62.363577 L torr mol^{-1}K^{-1}

T= Temperature

V= Volume of solution

Given:

T= 298K

V= 150 mL= 0.150 L

Given mass of unknown electrolyte= 15.2 mg = 15.2 x  10^{-3} g

Osmotic pressure= 8.44 torr

Molar mass= ?

For non-electrolytes:

πV = n RT

πV=\frac{m}{M}RT

Calculations:

Putting the given values in the formula:

8.44 x 0.150 =15.2 x 10^{-3}/ M x 62.36 x 298

1.266 = 282.5/M

M = 282.5/1.266

M = 223.14 g

Therefore,

The molar mass of the unknown non-electrolyte is 223.14g.

Learn more about Osmotic pressure here,

brainly.com/question/13680877

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7 0
2 years ago
If 980kJ of energy as heat are transferred to 6.2L of water at 291 K what will the final temperature be? The specific heat of wa
In-s [12.5K]

Answer:

Final temperature = T₂ = 328.815 K

Explanation:

Given data:

Given energy = 980 KJ = 980×1000= 980000 J

Volume = 6.2 L

Initial temperature =T₁= 291 K

Specific heat of water = 4.18 j /g .K

Final temperature = T₂ = ?

Formula:

Q = m. c . ΔT

ΔT = T₂ - T₁

we will first convert the litter into milliliter

6.2 × 1000 = 6200 mL

It is given in question that

1 mL = 1 g

6200 mL = 6200 g

Now we will put the values in formula,

Q = m. c . (T₂ - T₁)

980000 j = 6200 g . 4.18 j /g .K . (T₂ - 291 K)

980000 j = 25916 j/ k .  (T₂ - 291 K)

980000 j /  25916 j/ k =  T₂ - 291 K

37.8145 K + 291 K =T₂

T₂ = 328.815 K

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3 years ago
Compare and contrast earth and mars ?
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I hope this helps you

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