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KatRina [158]
3 years ago
8

A DC motor's magnet has a magnetic field that ____ the wire loop's magnetic field, therefore causing the loop to rotate.

Physics
2 answers:
jek_recluse [69]3 years ago
5 0

b. deflects. A DC motor's magnet has a magnetic field that <em><u>deflects</u></em> the wire loop's magnetic field, therefore causing the loop to rotate.

When a conductor, through which an electric current passes, is immersed in a magnetic field, it experiences a deflects force according to the Law of Lorentz creating as result that the loop rotate.

Liula [17]3 years ago
5 0

A DC motor's magnet has a magnetic field that deflects the wire loop's magnetic field, therefore causing the loop to rotate.

Answer : Option B

<u>Explanation:</u>

It is said that electric field is always associated with the magnetic field and they influence each other. When a wire carrying current is placed near a magnetic compass, the needle present in the compass will deflect showing that there is a magnetic field associated with the set up. Every magnet has a magnetic field associated with it which causes deflection thereby making the loop to rotate.

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The best activity for her to do to improve her range of motion is flexibility.

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7 0
1 year ago
Through what voltage must an αα-particle, with its charge of +2e+2e, be accelerated so that it has just enough energy to reach a
mezya [45]

Answer:5101.35v

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U = 1/(4×3.142×Eo)×(qQ)/r

Where r is distance between the charges and the nucleus

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V= 1/(4×3.142×Eo)×Q/(r+d)

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3 0
3 years ago
While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.
lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

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523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

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Answer:

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