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3 years ago

how much time would it take for the sound of a thunder to travel 1,500 meters if sound travelers at a speed of 330 m/sec?

Physics

1 answer:

inysia [295]3 years ago

8 0

(1,500 meters) x (1 sec/330 meters) =

(1,500 / 330) (meters-sec/meters) =

4.55 seconds

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I believe they are called Rhizomes.

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3 years ago

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The spring in the muzzle of a child's spring gun has a spring constant of 730 N/m. To shoot a ball from the gun, first the sprin

Korolek [52]

Answer:

a. V=11.84 m/s

b.x=0.052m

Explanation:

a).

Given

$K=730 N/m$ , $m=0.053kg$ , $h=1.90m$ .

$v_f^2=v_i^2+2*g*h$

$v_i^2=2*g*h=2*9.8m/s^2*1.9m$

$v_i=\sqrt{2*9.8m/s^2*1.9m}=\sqrt{37.24 m^2/s^2}$

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$v_i=V*sin(31)$

$V=\frac{v_i}{sin(31)}=\frac{6.1m/s}{sin(31)}$

$V=11.84 m/s$

b).

$K_k=\frac{1}{2}*K*x^2$

No friction on the ball so:

$x^2=\frac{2*K_k}{K}$

$x=\sqrt{\frac{2*0.053kg*9.8m/s^2*1.9m}{730N/m}}$

$x=\sqrt{2.7x10^{-3}m^2}=0.052m$

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3 years ago

Name of compounds a. H2Co3 b. NH4OH c.AlPO4 d.NaOH e.AuCI3

seraphim [82]

Answer:

a) Carbonic acid

b) ammonium hydroxide

c) Aluminum phosphate

d) Sodium hydroxide

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Explanation:

I hope this will help you buddy 

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3 years ago

A straight wire 0.10 m long carrying a current of 2.0 A is at right angles to a magnetic field. The force on the wire is 0.04 N.

Vladimir79 [104]

Answer:

The strength of magnetic field is 0.2 Tesla.

Explanation:

Data from the question is

Length (L) of wire ; L=0.10 m

Current in wire ; I= 2.0 A

Force on wire ; F = 0.04 N

Angle = Right angle So, $\theta$ $\thita = 90^{o}$

Now ,

We have to find the magnetic Field strength (B)

For this formula for Force on wire in magnetic field is

$F = I \times B \times L \times sin(\theta)$

Further modified as

$B = \frac{F}{I \times L \times sin(\theta)}$

Now insert values in the formula

$B = \frac{0.04N}{2.0A \times 0.10 m \times sin(90^{0})}$

$B = 0.2 T$

So, the strength of magnetic field is 0.2 Tesla.

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3 years ago

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