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3 years ago

9

A solution which has a solid solute is saturated at 25°C. It is then heated to 35°C. There is no change in the appearance of the

solution. What term would now be associated with this solution?
A.
unsaturated

B.
saturated

C.
oversaturated

D.
supersaturated

1 answer:

vampirchik [111]3 years ago

8 0

Answer:

C. oversaturated

Explanation:

Sana nakatulong

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A- 1000 m/s2<br> Xi-0m<br> Xf-0.75m<br> Vf-?

sleet_krkn [62]

Answer:

The final velocity of the object is, $v_{f}$ = 27 m/s

Explanation:

Given,

The acceleration of the object, a = 1000 m/s²

The initial displacement of the object, $x_{i}$ = 0 m

The final displacement of the object, $x_{f}$ = 0.75 m

The initial velocity of the object will be, $v_{i}$ = o m/s

The final velocity of the object, $v_{f}$ = ?

The average velocity of the object,

v = ( $x_{f}$ - $x_{i}$ )/ t

= 0.75 / t

The acceleration is given by the relation

a = v / t

1000 m/s² = 0.75 / t²

t² = 7.5 x 10⁻⁴

t = 0.027 s

Using the I equation of motion,

$v_{f}$ = u + at

Substituting the values

$v_{f}$ = 0 + 1000 x 0.027

= 27 m/s

Hence, the final velocity of the object is, $v_{f}$ = 27 m/s

8 0

4 years ago

A small sculpture made of brass (rho brass = 8470 kg/m 3 ) is believed to have a secret central cavity. The weight of the sculpt

GaryK [48]

Answer:

Volume of secret cavity = 4 x 10⁻⁶m³

Explanation:

The weight of the sculpture in air is 15.76 N

Mass of the sculpture = 1.61 kg

Mass = Volume x Density

1.61 = V x 8470

Volume of brass =1.90 x 10⁻⁴ m³

When it is submerged in water, the weight is 13.86 N.

That is

Weight of sculpture - Weight of water displaced = 13.86 N

15.76 - Weight of water displaced = 13.86

Weight of water displaced = 1.9 N

Mass of water displaced = 0.194 kg

Mass = Volume x Density

0.194 = V x 1000

Volume of water displaced =1.94 x 10⁻⁴ m³

Volume of secret cavity = Volume of water displaced - Volume of brass material

Volume of secret cavity = 1.94 x 10⁻⁴-1.94 x 10⁻⁴ = 0.04x 10⁻⁴ = 4 x 10⁻⁶m³

7 0

4 years ago

What is 7.325 NS x 10 to the 549 power GS equal?

Alexxandr [17]

Idrk sorry ___\........../.....

5 0

3 years ago

Consider a single photon with a wavelength of lambda, a frequency of nu, and an energy of E. What is the wavelength, frequency,

BARSIC [14]

Answer: lambda $\lambda$ , nu $\nu$ , and 100E

Explanation:

The energy $E$ of a photon is given by:

$E=h\nu$ (1)

Where:

$h$ is the Planck constant

$nu$ is the frequency

On the other hand, we have an expression that relates the frequency of the photn with its wavelength $\lambda$ :

$nu=\frac{c}{\lambda}$ (2) where $c$ is the speed of light

Substituting (2) in (1):

$E=h\frac{c}{\lambda}$ (3) This is the energy for a single photon

For 100 photons, the energy is:

$100E=100(h\frac{c}{\lambda})=100h\nu$ (3)

Where the wavelength and the frequency of the light remains constant.

Therefore, the answer is:

$\lambda$ , $\nu$ , and 100E

5 0

3 years ago

A brass rod with a length of 1.22 m and a cross-sectional area of 2.19 cm2 is fastened end to end to a nickel rod with length L

GaryK [48]

Answer:

a) L₂ = 0.676 m

b) σ₁ = 2.28*10⁸ N/m²

σ₂ = 9.62*10⁸ N/m²

c) ε₁ = 0.00253678

ε₂ = 0.00457875

Explanation:

Given info

L₁ = 1.22 m

A₁ = 2.19 cm² = 2.19*10⁻⁴ m²

L₂ = ?

A₂ = 0.52 cm² = 0.52*10⁻⁴ m²

P = 5.00*10⁴ N

E₁ = 9*10¹⁰ N/m²

E₂ = 2.1*10¹¹ N/m²

In order to get the length L of the nickel rod if the elongations of the two rods are equal, we can say that

ΔL₁ = ΔL₂ ⇒ P*L₁/(A₁*E₁) = P*L₂/(A₂*E₂)

⇒ L₂ = A₂*E₂*L₁ / (A₁*E₁)

⇒ L₂ = (0.52*10⁻⁴ m²)*(2.1*10¹¹ N/m²)*(1.22 m) / (2.19*10⁻⁴ m²*9*10¹⁰ N/m²)

⇒ L₂ = 0.676 m

The stress in the brass rod is obtained as follows

σ₁ = P/A₁ ⇒ σ = 5.00*10⁴ N / 2.19*10⁻⁴ m² = 2.28*10⁸ N/m²

The stress in the niquel rod is obtained as follows

σ₂ = P/A₂ ⇒ σ = 5.00*10⁴ N / 0.52*10⁻⁴ m² = 9.62*10⁸ N/m²

The strain in the brass rod is obtained as follows

σ₁ = E₁*ε₁ ⇒ ε₁ = σ₁ / E₁

⇒ ε₁ = 2.28*10⁸ N/m² / 9*10¹⁰ N/m² = 0.00253678

The strain in the niquel rod is obtained as follows

σ₂ = E₂*ε₂ ⇒ ε₂ = σ₂ / E₂

⇒ ε₂ = 9.62*10⁸ N/m² / 2.1*10¹¹ N/m² = 0.00457875

3 0

3 years ago