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3 years ago

A corvette starts from rest and travels 69.0 meters in 50 s. What is its acceleration?

Physics

1 answer:

devlian [24]3 years ago

4 0

Answer:

0.0552 m/s²

Explanation:

Given:

Δx = 69.0 m

v₀ = 0 m/s

t = 50 s

Find: a

Δx = v₀ t + ½ at²

69.0 m = (0 m/s) (50 s) + ½ a (50 s)²

a = 0.0552 m/s²

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How does fungi, snails, earthworms, and pill bugs return nutrients to the ecosystem?

luda_lava [24]

They decompose and leave their nutrients in the earth.

4 0

3 years ago

A moon orbits a planet every 42 hours with a mean orbital radius of .002819 AU. The mass of the moon is 8.932 x 1022 kg. Using N

Pepsi [2]

Answer:

The mass of the planet is $1.9407\times10^{27}\ kg$

Explanation:

Given that,

Time period = 42 hours = 151200 sec

Orbital radius = 0.002819 AU = 421716397.5 m

Mass of moon $m=8.932\times10^{22}\ kg$

We need to calculate the mass of the planet

Using Kepler’s third law

$T^2\propto a^3$

$T^2=\dfrac{4\pi^2}{G(M+m)}\times a^3$

Where, a = orbital radius

T = time period

G = gravitational constant

M = mass of moon

m = mass of planet

Put the value into the formula

$(151200)^2=\dfrac{4\pi^2}{6.673\times10^{-11}(8.932\times10^{22}+m)}\times(421716397.5)^3$

$(8.932\times10^{22}+m)=\dfrac{4\pi^2}{6.673\times10^{-11}}\times\dfrac{(421716397.5)^3}{(151200)^2}$

$(8.932\times10^{22}+m)=1.94087\times10^{27}$

$m=1.94087\times10^{27}-8.932\times10^{22}$

$m=1.9407\times10^{27}\ kg$

Hence, The mass of the planet is $1.9407\times10^{27}\ kg$

8 0

4 years ago

What rock type does the principle of superposition apply to and how is the principle of superposition used to study the history

Effectus [21]

New rock get on top of old rock to form new layers of rock

3 0

4 years ago

Can someone help me understand this assignment and give me some hints and tips on what I should do, please?

katen-ka-za [31]

First you have to note down you horoscope for 2-3 days.

Daily observe what is written in your horoscope is true or not. You can observe your entire day movements.

Now you have to conclude whether your horoscope was true or not and you have to write an essay explaining what had happened to you in past observation and conclude whether you believe in astronomy or not depending on your observations

6 0

4 years ago

A certain laser outputs pure red light (photon energy 1.8 eV) with power 550 milliwatts (0.55 watts). How many photons per secon

Klio2033 [76]

We want to find how many photons per second a laser emits given that we know the energy of a single photon and the power of the laser, we will get:

1.90712*10^18 photons per second.

So we know that the photon energy is 1.8 eV, and the laser power is:

P = 0.55 watts

Remember that:

1 watt = 1 J/s

And:

1 eV = 1.60218*10^(-19) J

Then we can convert the two values that we have so we have both in joules:

Power = P = 0.55 J/s

Energy = 1.8 eV = 1.8*(1.60218*10^(-19) J) = 2.883924*10^(-19) J

The number of photons emitted per second is just the quotient between the power and the energy of a single photon, we have:

Number = (0.55 J/s)/(2.883924*10^(-19) J) = 1.90712*10^18 photons per second.

If you want to learn more, you can read:

brainly.com/question/20343793

5 0

3 years ago