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svlad2 [7]
4 years ago
9

The graph describes the motion of an object

Physics
2 answers:
ExtremeBDS [4]4 years ago
8 0

Answer:

Explanation:

Answer: the object moves with constant velocity from A to B. It remains stationary from B to C. It moves with constant velocity from C to D.

Alik [6]4 years ago
6 0

Answer: the object moves with <u>constant velocity</u> from A to B. It <u>remains stationary</u> from B to C. It moves with <u>constant velocity </u>from C to D.

Explanation:

This Position vs Time graph shows how the position X changes with time t and this is the definition of the velocity V. This can be expressed as:

V=\frac{\Delta X}{\Deltat}=\frac{X_{2}-X_{1}}{t_{2}-t_{1}}

In the first segment AB, if we take two points (X_{1},t_{1}) and  (X_{2},t_{2}) the resultant velocity will be the same if we repeat the same calculation with any two points in this segment. This means the object  is moving at constant velocity.

In the segment BC, there is no change of the position in time, therefore the object is stationary during this segment.

Finally, in segment CD, the object has the same behavior as segment AB, hence it is moving with constant velocity again.

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When water freezes, its volume increases by 9.05%. What force per unit area is water capable of exerting on a container when it
AnnZ [28]

Answer:

The Pressure is 0.20 MPa.

(b) is correct option.

Explanation:

Given that,

Change in volume = 9.05%

{tex]\dfrac{\Delta V}{V_{0}}=0.0905[/tex]

We know that.

The bulk modulus for water

B=0.20\times10^{10}\ N/m^2

We need to calculate the pressure difference

Using formula bulk modulus formula

B=\Delta P\dfrac{V_{0}}{\Delta V}

\Delta P=B\dfrac{\Delta V}{V_{0}}

\Delta P=0.2\times10^{10}\times0.0905

\Delta P=0.2\times10^{6}\ Pa

\Delta P=0.20 MPa

Hence, The Pressure is 0.20 MPa.

6 0
4 years ago
Upthrust given by Water to the body
erica [24]

Answer:

According to Archimedes principle the upthrust on the body is equal to the weight of the water displaced by the body. ... Here, the mass would be the net difference in the weight of the object.

7 0
3 years ago
Which is true about Earth's energy budget?
REY [17]

Answer:

I think is B but I'm not sure

5 0
3 years ago
Calculate the amount of force required to produce motion in a car of 1000kg with an acceleration of 5m/s square.​
atroni [7]

Answer:

5000 N

Explanation:

F=ma

=1000*5

=5000N

4 0
3 years ago
Read 2 more answers
A man pulled a 13.0 kg object 11.8 cm vertically with his teeth. (a) How much work (in J) was done on the object by the man in t
jonny [76]

Answer:

(a)The work done by the man is -15.03J.

(b)The force exerted on the object is 127.4N.

Explanation:

Mass of the object pulled by the man is -13kg

Object is lifted 11.8 cm vertical with his teeth it means (displacement = +11.8cm = +0.118m)

Acceleration due to gravity is 9.8 \mathrm{m} / \mathrm{s}^{2}

(a) <u>Calculating the work done</u>:

Work done = mgh

Where "m" is mass of an object, "g" is acceleration due to gravity and "h" is the displacement.

\text { Work }=-13 \times 9.8 \times(+0.118 \mathrm{m})

\text { Work }=-15.03 \mathrm{J}

The work done by the man is -15.03J.

(b) <u>Calculating the force</u>:

Probably the man and the object are close to the exterior of the earth. If the rigidity required to maintained the object of consistent velocity interior the gravitational field of the earth is \mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2}

Thus the weight of the object is balanced by the force of the man's teeth on the object. That is

F = mg

\mathrm{F}=13 \times 9.8

F = 127.4N

The force exerted on the object is 127.4N.

4 0
3 years ago
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