___________ charges a neutral body by touching it with a charged body.

Kelly Clarkson is running between the Patronas towers in Kuala Lumpur on a tightrope at a speed of 15 m/s. Kelly currently weigh

Tomtit [17]

KE = 8887.5 J

<h3>Further explanation</h3>

Given

speed = 15 m/s

weight = 79 kg

Required

KE-Kinetic energy

Solution

Energy is the ability to do work

Energy because its motion is expressed as Kinetic energy (KE) which can be formulated as:

$\large {\boxed {\bold {KE = \frac {1} {2} mv ^ 2}}}$

Input the value :

KE = 1/2 x 79 kg x 15² m/s²

KE = 8887.5 J

8 0

3 years ago

Read 2 more answers

Let's practice calculating the frictional force of a skier on old "woody" skis and wet snow. The skier has a mass of 58 kg. The

kicyunya [14]

Answer:

Kinetic frictional force will be equal to 56.84 N

Explanation:

We have given mass of the skier m = 58 kg

Acceleration due to gravity $g=9.8m/sec^2$

Coefficient of kinetic friction $\mu _k=0.1$

We have to find the kinetic frictional force

Kinetic frictional force is given by

$F_K=\mu _Kmg=0.1\times 58\times 9.8=56.84N$

So kinetic frictional force will be equal to 56.84 N

8 0

4 years ago

A record of travel along a straight path is as follows: 1. Start from rest with constant acceleration of 2.24 m/s2 for 10.0 s. 2

valentina_108 [34]

Answer:

1817.448 m

Explanation:

Given:

Initial acceleration = 2.24 m/s²

Time for acceleration = 10 s

From Newton's equation of motion

v = u + at

here v is the final velocity after the acceleration

v = 0 + 2.24 × 10 = 22.4 m/s

thus,

the displacement during acceleration

From Newton's equation of motion

$s_1=ut+\frac{1}{2}at^2$

where,

s is the distance

u is the initial speed = 0 m/s as starting from rest

a is the acceleration

t is the time

on substituting the respective values, we get

$s_1=0\times10+\frac{1}{2}\times2.24\times10^2$

or

s₁ = 112 m

for case 2

time = 1.25 minute = 1.25 × 60 = 75 seconds

displacement, s₂ = v × t = 22.4 × 75 = 1680 m

for the case 3

acceleration = - 9.86 m/s²

now,

the final velocity for the second case is the initial velocity for this case

thus,

$s_3=22.4\times2.27+\frac{1}{2}(-9.86)\times2.27^2$

or

s₃ = 50.848 - 25.40 = 25.448 m

hence,

the total displacement = s₁ + s₂ + s₃ = 112 m + 1680 m + 25.448 m

= 1817.448 m

3 0

3 years ago

A particular light source gives off light waves with a measured wavelength of

Umnica [9.8K]

The frequency of the light source is 1.5 x 10¹⁵ Hz.

<h3>Frequency of the light source</h3>

The frequency of the light source is determined using the following equations;

c = fλ

where;

c is speed of light

f is the frequency

λ is the wavelength

f = (3 x 10⁸) / (2 x 10⁻⁷)

f = 1.5 x 10¹⁵ Hz

Thus, the frequency of the light source is 1.5 x 10¹⁵ Hz.

Learn more about frequency of light here: brainly.com/question/10728818

3 0

3 years ago

2×3.14√(1.0m/(9.8〖ms〗^(-1) )=)

il63 [147K]

This is the period in a simple harmonic motion which is 2 seconds in this question.

<h3>What is Period ?</h3>

The period of an oscillatory object can be defined as the total time taken by a vibrating body to make one complete revolution about a reference point.

We are given the below question

2×3.14√(1.0m/(9.8〖ms〗^(2) )= T

This question can as well be expressed as

2π√(L/g) which is equal to period T.

In a nut shell, Period T = 2×3.14√(1.0m/9.8)

T = 6.28√0.102

T = 6.28 × 0.32

T = 2.006 s

Therefore, the period T of the oscillation is 2 seconds approximately.

Learn more about Period here: brainly.com/question/12588483

#SPJ1

8 0

1 year ago