Answer:
I only know answer A and it's 2825.28 N/m, with rounding it's 2825.5
Explanation:
Use the m*g*h=1/2*k*x^2 equation
96*9.81*60=1/2*k*2^2
5650.56=2k
5650.56/2=2825.28N/m
Answer and Explanation:
In optics, a CoC(Circle of Confusion) is defined the minimum cross section of a paraxial bundle of rays made by a lens which is sphero-cylindrical type and can be viewed as an optical spot, which do not converge perfectly at the focus while a point source is being imaged due to spherical aberration.
The Circle of Confusion is also referred to as circle of indistinctness or a blur spot
Answer:
The initial speed of bullet is "164 m/s".
Explanation:
The given values are:
mass of bullet,
![m'=9.00 \ g](https://tex.z-dn.net/?f=m%27%3D9.00%20%5C%20g)
or,
![=0.009 \ kg](https://tex.z-dn.net/?f=%3D0.009%20%5C%20kg)
mass of wooden block,
![m=1.20 \ kg](https://tex.z-dn.net/?f=m%3D1.20%20%5C%20kg)
speed,
![s=0.390 \ m](https://tex.z-dn.net/?f=s%3D0.390%20%5C%20m)
Coefficient of kinetic friction,
![\mu=0.20](https://tex.z-dn.net/?f=%5Cmu%3D0.20)
As we know,
The Kinematic equation is:
⇒ ![v^2=u^2+2as](https://tex.z-dn.net/?f=v%5E2%3Du%5E2%2B2as)
then,
Initial velocity will be:
⇒ ![u=v^2-2as](https://tex.z-dn.net/?f=u%3Dv%5E2-2as)
![=v^2-2 \mu gs](https://tex.z-dn.net/?f=%3Dv%5E2-2%20%5Cmu%20gs)
On substituting the given values, we get
⇒ ![u=\sqrt{0-2\times 0.20\times 9.8\times 0.390}](https://tex.z-dn.net/?f=u%3D%5Csqrt%7B0-2%5Ctimes%200.20%5Ctimes%209.8%5Ctimes%200.390%7D)
![=\sqrt{-1.5288}](https://tex.z-dn.net/?f=%3D%5Csqrt%7B-1.5288%7D)
![=1.23 \ m/s](https://tex.z-dn.net/?f=%3D1.23%20%5C%20m%2Fs)
As we know,
The conservation of momentum is:
⇒ ![mu=m'u'](https://tex.z-dn.net/?f=mu%3Dm%27u%27)
or,
⇒ Initial speed, ![u'=\frac{mu}{m'}](https://tex.z-dn.net/?f=u%27%3D%5Cfrac%7Bmu%7D%7Bm%27%7D)
On substituting the values, we get
⇒ ![=\frac{1.20\times 1.23}{0.009}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1.20%5Ctimes%201.23%7D%7B0.009%7D)
⇒ ![=\frac{1.476}{0.009}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1.476%7D%7B0.009%7D)
⇒
Answer:
B: Horizontally to the left
Explanation:
Horizontal velocity is always constant throughout the entire trajectory of the rocket and acts in the horizontal direction in which the rocket was launched. This is because gravity only acts in the downwards vertical direction.
So in order words at peak height, horizontal velocity is in the horizontal direction in which the rocket was launched.
So if it was to the left, then direction is left but if right, then direction is right.
Looking at the options, the most appropriate will be:
Horizontally to the left