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Airida [17]
3 years ago
10

Which statement best explains the relationship between the electric force between two charged objects and the distance between t

hem?
A.
As the distance increases by a factor, the electric force increases by the square of that factor.
B.
As the distance increases by a factor, the electric force increases by twice that factor.
C.
As the distance increases by a factor, the electric force decreases by twice that factor.
D.
As the distance increases by a factor, the electric force decreases by the same factor.
E.
As the distance increases by a factor, the electric force decreases by the square of that factor.
Physics
1 answer:
Thepotemich [5.8K]3 years ago
8 0

Answer: a

Explanation:

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A stone with a mass of 0.100kg rests on a frictionless, horizontal surface. A bullet of mass 2.50g traveling horizontally at 500
jolli1 [7]

Answer:

Explanation:

Given that:

mass of stone (M) = 0.100 kg

mass of bullet (m) = 2.50 g = 2.5  ×10 ⁻³ kg

initial velocity of stone (u_{stone}) = 0 m/s

Initial velocity of bullet (u_{bullet}) = (500 m/s)i

Speed of the bullet after collision (v_{bullet}) = (300 m/s) j

Suppose we represent (v_{stone}) to be the velocity of the stone after the truck, then:

From linear momentum, the law of conservation can be applied which is expressed as:

m*u_{bullet} + M*{u_{stone}}= mv_{bullet}+Mv_{stone}

(2.50*10^{-3} \ kg) (500)i+0 = (2.50*10^{-3} \ kg)(300 \ m/s)j + (0.100 \ kg)v_{stone}

(2.50*10^{-3} \ kg) (500)i- (2.50*10^{-3} \ kg)(300 \ m/s)j=  (0.100 \ kg)v_{stone}

v_{stone}= (1.25\  kg.m/s)i-(0.75\ kg m/s)j

v_{stone}= (12.5\  m/s)i-(7.5\ m/s)j

∴

The magnitude now is:

v_{stone}=\sqrt{ (12.5\  m/s)^2-(7.5\ m/s)^2}

\mathbf{v_{stone}= 14.6 \ m/s}

Using the tangent of an angle to determine the direction of the velocity after the struck;

Let θ represent the direction:

\theta = tan^{-1} (\dfrac{-7.5}{12.5})

\mathbf{\theta = 30.96^0 \ below \ the \ horizontal\ level}

5 0
3 years ago
While running around the track at school, Milt notices that he runs due East on the 100m homestretch and due West on the 100m ba
Yuri [45]
Answer a would be correct since velocity is a vector and has a magnitude and a direction. In this case v₁ = - v₂.
8 0
3 years ago
Read 2 more answers
I need help on number 5. We need to use one of the four kinematics equations.
Gnom [1K]

ANSWER

35.02m

EXPLANATION

Parameters given:

Initial velocity, u = 26.2 m/s

When the vase reaches its maximum height, its velocity becomes 0 m/s. That is the final velocity.

We can now apply one of Newton's equations of motion to find the height:

v^2=u^2-2as

where a = g = acceleration due to gravity = 9.8 m/s²

Therefore, we have that:

\begin{gathered} 0=26.2^2-2(9.8)s \\ \Rightarrow19.6s=686.44 \\ s=\frac{686.44}{19.6} \\ s=35.02m \end{gathered}

That is the height that the vase will reach.

5 0
1 year ago
How can icalculate 3 seconds and 5 meters into a speed?
topjm [15]
To find speed you have to divide distance by time. In this case:

5 meters➗3 seconds = about 1.66666666 and so on m/s.

You could round to 1.67 or 1.7 if you'd like.
8 0
3 years ago
A car starts from rest with an acceleration of 2.84 m/s2 at the instant when a second car moving with a velocity of 25.7 m/s pas
vredina [299]

Answer:

464.69 m

Explanation:

First car

s=ut+\frac{1}{2}at^2\\\Rightarrow s=0\times t+\frac{1}{2}2.84t^2\\\Rightarrow s=1.42t^2

Second car

Distance = Speed × Time

\text{Distance}=25.7t

Here, the time taken and the distance traveled will be the same

Equating the two equations

1.42t^2=25.7t\\\Rightarrow t=\frac{25.7}{1.42}\\\Rightarrow t=18.09\ s

So, the first would have to move 1.42t^2=1.42\times 18.09^2=464.69\ m in order to overtake the second car.

7 0
3 years ago
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