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3 years ago

10

Which statement best explains the relationship between the electric force between two charged objects and the distance between t

hem?
A.
As the distance increases by a factor, the electric force increases by the square of that factor.
B.
As the distance increases by a factor, the electric force increases by twice that factor.
C.
As the distance increases by a factor, the electric force decreases by twice that factor.
D.
As the distance increases by a factor, the electric force decreases by the same factor.
E.
As the distance increases by a factor, the electric force decreases by the square of that factor.

1 answer:

Thepotemich [5.8K]3 years ago

8 0

Answer: a

Explanation:

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(b) Now the mass of the air in room,

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Read 2 more answers

Sixty identical drippers, each with a hole of diameter 1.00 mm, are used to water a yard. If the water in the main pipe of diame

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Answer:

a

$V = 5.30 *10^{-2} \ m^3$

b

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Explanation:

From the question we are told that

The number of identical drippers is n = 60

The diameter of each hole in each dripper is $d = 1.0 \ mm = 0.001 \ m$

The diameter of the main pipe is $d_m = 2.5 \ cm = 0.025 \ m$

The speed at which the water is flowing is $v = 3.00 \ cm/s = 0.03 \ m/s$

Generally the amount of water used in one hour = 3600 seconds is mathematically represented as

$V = A * v * 3600$

Here A is the area of the main pipe with value

$A = \pi * \frac{d^2}{4}$

=> $A = 3.142 * \frac{0.025^2}{4}$

=> $A = 0.0004909 \ m^2$

So

=> $V = 0.0004909 * 0.03 * 3600$

=> $V = 5.30 *10^{-2} \ m^3$

Generally the area of the drippers is mathematically represented as

$A_1= n * \pi \frac{d^2}{4}$

=> $A_1 = 60 * 3.142 * \frac{0.001 ^2}{4}$

=> $A_1 = 4.713 *10^{-5} \ m^2$

Generally from continuity equation we have that

$Av = A_1 v_1$

=> $0.0004909 * 0.03 = 4.713 *10^{-5} * v_1$

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