Answer:
The balanced equations are as follows:
✅ FeCl₃ + 3NH₄OH ➡ Fe(OH)₃ + 3NH₄Cl
✅ CH₄ + O₂ ➡ CO₂ + 2H₂O
✅ 2Fe + 3H₂SO₂ ➡ Fe₂(SO₂)₃ + 3H₂
✅ PCl₅ + 4H₂O ➡ 5HCl + H₃PO₄
Explanation:
In the equation, FeCl₃ + 3NH₄OH ➡ Fe(OH)₃ + 3NH₄Cl, Charlie will adjust the number of atoms in NH₄OH in order for NH₄, Cl and OH to balance in the product side. 3 was placed in front of NH₄OH and NH₄Cl in order the balance it.
In the equation, CH₄ + O₂ ➡ CO₂ + 2H₂O, Charlie will adjust the number of atoms in H₂O. 2 was placed in front of H₂O in order to balance the atoms in the reactant and product sides.
In the equation, 2Fe + 3H₂SO₂ ➡ Fe₂(SO₂)₃ + 3H₂, Charlie will adjust the number of atoms in the reactant side in order for the product side to be balanced.
In the equation, PCl₅ + 4H₂O ➡ 5HCl + H₃PO₄, Charlie will adjust the number of atoms in H₂O and HCl for the equation to be balanced. 4 and 5 were placed in front of H₂O and HCl respectively in order for the equation to be balanced.
In chemical equations, it is required that the number of atoms of each element found in the reactants must be equal to the number of atoms of each element found in the products. This makes the chemical equation balanced.
Answer:
1. Kinetic Energy = 0.0161 Joules
2. Height = 0.0137m
Explanation:
Given
Length of Rod, l = 0.64m
Mass, m = 120g = 0.12kg
Angular speed, w = 1.40 rad/s
a.
Calculating the Rod's kinetic energy
This is calculated by
Kinetic Energy = ½Iw²
Where I = rotational inertia of the rod about an axis.
This is calculated as follows;
I = Icm + mh²
I = ImL² + m(L/2)²
I = 1/12 * 0.12 * 0.64² + 0.12 * (0.64/2)²
I = 0.016384 kgm²
By substituton
KE = ½Iw² becomes
KE = ½ * 0.016384 * 1.40²
KE = 0.01605632J
KE = 0.0161 Joules
2. Using the total conservation of momentum;
K + U = Kf + V
Where K = Initial Kinetic Energy of the rod at lowest point.
U = Initial gravitational potential energy of the rod at lowest point
Kf = Final Kinetic Energy of the rod at maximum height = 0 J
V = Final gravitational potential energy of the rod at maximum height
So, K + U = Kf + V become
K + U = 0 + V
K + U = V
K = V - U = mgh
substitute 0.01605632J for K
0.01605632J = mgh
h = 0.01605632J/mg
h = 0.01605632J/(0.12 * 9.8)
h = 0.013653333333333
h = 0.0137m
Answer:
Explanation:
For resistance of a wire , the formula is as follows .
R = ρ L/S
where ρ is specific resistance , L is length and S is cross sectional area of wire .
for first wire resistance
R₁ = ρ 3L/3a = ρ L/a
for second wire , resistance
R₂ = ρ 3L/6a
= .5 ρ L/a
For 3 rd wire resistance
R₃ = ρ 6L/3a
= 2ρ L/a
For fourth wire , resistance
R₄ = ρ 6L/6a
= ρ L/a
So the smallest resistance is of second wire .
Its resistance is .5 ρ L/a