Answer:i belive the answer is E = 1/2 mv^2
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Here, we are required to find the relationship between balls of different mass(a measure of weight) and different volumes.
- 1. Ball A will have the greater density
- 2. Ball C and Ball D have the same density.
- 3. Ball Q will have the greater density.
- 4. Ball X and Y will have the same density
The density of an object is given as its mass per unit volume of the object.
Mathematically;.
For Case 1:
- Va = Vb and Ma = 2Mb
- D(b) = (Mb)/(Vb) and D(a) = 2(Mb)/Vb
- Therefore, the density of ball A,
- D(a) = 2D(b).
- Therefore, ball A has the greater density.
For Case 2:
- D(c) = (Mc)/(Vc) and D(d) = (1/3)Md/(1/3)Vd
- Therefore, ball C and D have the same density
For Case 3:
- Vp = 2Vq and Mp = Mq
- D(p) = (Mq)/2(Vq) and D(q) = (Mq)/Vq
- Therefore, the density of ball P is half the density of ball Q
- Therefore, ball Q has the greater density.
For case 4:
Therefore, Ball X and Ball Y have the same density.
Read more:
brainly.com/question/18110802
D, the plant takes Solar/Light energy and converts it into chemical energy.
Answer:
h = 40.37 m
Explanation:
We will apply the law of conservation of energy to the skier in this case, as follows:
where,
m = mass of skier = 77 kg
g = acceleration due to gravity = 9.81 m/s²
vf = final speed = 30 m/s
vi = initial speed = 2 m/s
W_friction = Work done by friction and air resistance = 4000 J
Therefore,
![(77\ kg)(9.81\ m/s^2)h = \frac{1}{2}(77\ kg)[(30\ m/s)^2-(2\ m/s)^2] - 4000\ J\\\\h = \frac{34496\ J - 4000\ J}{755.37\ N}\\\\](https://tex.z-dn.net/?f=%2877%5C%20kg%29%289.81%5C%20m%2Fs%5E2%29h%20%3D%20%5Cfrac%7B1%7D%7B2%7D%2877%5C%20kg%29%5B%2830%5C%20m%2Fs%29%5E2-%282%5C%20m%2Fs%29%5E2%5D%20-%204000%5C%20J%5C%5C%5C%5Ch%20%3D%20%5Cfrac%7B34496%5C%20J%20-%204000%5C%20J%7D%7B755.37%5C%20N%7D%5C%5C%5C%5C)
<u>h = 40.37 m</u>
