Question

Calculate 9 ∙ 10-5 divided by 3 ∙ 10-9.

Answer 1

Explanation:

In this case, we need to divide two number where

First number, $n_1=9\times 10^{-5}$

Second number, $n_2=3\times 10^{-9}$

$\dfrac{n_1}{n_2}=\dfrac{9\times 10^{-5}}{3\times 10^{-9}}$

We know that, 3 × 3 = 9

So, $\dfrac{n_1}{n_2}=\dfrac{3\times 10^{-5}}{10^{-9}}$

Since, $\dfrac{a^x}{a^y}=a^{x-y}$

Also, $a^x.a^y=a^{x+y}$

Here, $\dfrac{10^{-5}}{10^{-9}}=a^{-5-(-9)}=10^4$

$\dfrac{n_1}{n_2}=3\times 10^{4}$

So, on dividing two numbers we get $3\times 10^{4}$. Hence, this is the required solution.

Answer 2

[(9)(10-5)]/[(3)(10-9)]
[(9)(5)]/[(3)(1)]
45/3
15
Hope this helps!