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3 years ago

Select the major problems associated with the production of nuclear energy.

Physics

2 answers:

Rashid [163]3 years ago

8 0

Answer:

hazardous solid wastes

potential reactor accidents

harm to animal and plant life

Explanation:

liberstina [14]3 years ago

3 0

Hazardous solid wastes

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Did i get any of these answers right if not what do i have to change

gregori [183]

Answer:

You got them right

8 0

3 years ago

Two forces are acting on an object, but the net force on the object is O N. For the net

Alenkinab [10]

Answer:

A. The forces are the same size and in opposite directions.

Explanation:

Just as an opposite number will cancel a number: -1 +1 = 0, so an opposite force will cancel a force, with the result that the net is zero.

6 0

3 years ago

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You attach a meter stick to an oak tree, such that the top of the meter stick is 2.27 meters above the ground. later, an acorn f

Alexandra [31]

The acorn was at a height of <u>4.15 m</u> from the ground before it drops.

The acorn takes a time t to fall through a distance h₁, which is the length of the scale. When the acorn reaches the top of the scale, its velocity is u.

Calculate the speed of the acorn at the top of the scale, using the equation of motion,

$s=ut+ \frac{1}{2} at^2$

Since the acorn falls freely under gravity, its acceleration is equal to the acceleration due to gravity g.

Substitute 2.27 m for s (=h₁), 0.301 s for t and 9.8 m/s² for a (=g).

$s=ut+ \frac{1}{2} at^2\\ (2.27 m)=u(0.301s)+\frac{1}{2}(9.8m/s^2)(0.301s)^2\\ u=\frac{1.8261m}{0.301s} =6.067m/s$

If the acorn starts from rest and reaches a speed of 6.067 m/s at the top of the scale, it would have fallen a distance h₂ to achieve this speed.

Use the equation of motion,

$v^2=u^2+2as$

Substitute 6.067 m/s for v, 0 m/s for u, 9.8 m/s² for a (=g) and h₂ for s.

$v^2=u^2+2as\\ (6.067m/s)^2=(0m/s)^2+2(9.8m/s^2)h_2\\ h_2=\frac{(6.067m/s)^2}{2(9.8m/s^2)} =1.878 m$

The height h above the ground at which the acorn was is given by,

$h=h_1+h_2=(2.27 m)+(1.878 m)=4.148 m$

The acorn was at a height <u>4.15m</u> from the ground before dropping down.

3 0

3 years ago

At a depth of 10.9 km, the Challenger Deep in the Marianas Trench of the Pacific Ocean is the deepest site in any ocean. Yet, in

bearhunter [10]

Answer:

$P = 1.09 \times 10^8 Pa$

Explanation:

As we know that the pressure inside the liquid level is given as

$P = \rho g h + P_o$

here we have

$\rho = 1024 kg/m^3$

h = 10.9 km

also we know that

$P_o = 1.01 \times 10^5 Pa$

now we have

$P = (1.01 \times 10^5) + (1024)(9.81)(10.9 \times 10^3)$

$P = 1.09 \times 10^8 Pa$

8 0

3 years ago

With a force of 5 newtons, Amanda pushes the stack of books to the right. At the same time, Jeremy, her little brother, pushes t

Vaselesa [24]

Its letter C. 5N to the left. Since Jeremy's force in Newtons are higher than Amanda's (in newtons), and since Jeremy's force directs to the left, then the direction of the force will be to the LEFT. Then subtract the higher one to the lower one so that would be: 10N-5N=5N. So it is C. 5N to the left.

5 0

3 years ago

Read 2 more answers