All categories

4 years ago

A sports car of mass 1000 kg can accelerate from rest to 27 m/s in 7.0 s. what is the average forward force on the car?

Physics

1 answer:

Marysya12 [62]4 years ago

8 0

The average force on the car=3857 N

Explanation:

mass of car= 1000 kg

initial velocity= Vi=0

Final velocity= Vf=27 m/s

time= t= 7 s

using the kinematic equation,

Vf= Vi + at

27=0+a (7)

a=3.857 m/s²

Now the force is given by F= m a

F=1000 (3.857)

F=3857 N

You might be interested in

in the two cases shown the mass and the spring are identical but the amplitude of the simple harmonic motion is twice as big in

Ira Lisetskai [31]

The maximum velocities in the two cases related are Vmax,2 = 2 Vmax,1

Simple harmonic motion :

In physics, simple harmonic motion is the repeated back-and-forth motion through an equilibrium, or center, position so that the maximum displacement on one side of this position is equal to the maximum displacement on the other. Each whole vibration occurs at the same time interval.

Complete question:

In the two cases shown the mass and the spring are identical but the amplitude of the simple harmonic motion is twice as big in Case 2 as in Case 1.

1)How are the maximum velocities in the two cases related?

Vmax,2 = Vmax,1

Vmax,2 = 2 Vmax,1

Vmax,2 = 4 Vmax,1

To learn more about simple harmonic motion visit: brainly.com/question/28208332

#SPJ4

6 0

1 year ago

A 259-kV power transmission line carrying 429 A is hung from grounded metal towers by ceramic insulators, each having a 0.71×109

ella [17]

Answer:

The resistance is $7.47\times10^{6}\ \Omega$ .

Explanation:

Given that,

Power = 259 kV

Current = 429 A

Resistance $R=0.71\times10^{9}\ Omega$

We need to calculate the current in each insulator

Using formula of current

$I=\dfrac{P}{R}$

Put the value into the formula

$I=\dfrac{259\times10^{3}}{0.71\times10^{9}}$

$I=3.64\times10^{-4}\ A$

So all 95 insulators are in parallel

We need to calculate the resistance

Using formula of resistance

$\dfrac{1}{R}=\sum_{i=1}^{95}\dfrac{1}{R_{i}}$

Put the value into the formula

$\dfrac{1}{R}=\dfrac{95}{0.71\times10^{9}}$

$\dfrac{1}{R}=1.338\times10^{-7}$

$R=\dfrac{1}{1.338\times10^{-7}}$

$R=7473841.5=7.47\times10^{6}\ \Omega$

Hence, The resistance is $7.47\times10^{6}\ \Omega$ .

8 0

4 years ago

Limestone cave can develop when Limestone rock is weathered. The weathering of the rock leaves an empty space that forms the cav

Ymorist [56]

Answer:

Wind blowing across the surface eroded the limestone.

Explanation:

4 0

3 years ago

Read 2 more answers

A longitudinal wave is also known as a(n) _____ wave.

Furkat [3]

A longitudinal wave is also known as an oscillating wave. These waves affect the medium they are traveling through by disrupting what is either directly in front of behind them as they move.

4 0

3 years ago

Read 2 more answers

HELP PLZ! A parachutist jumps out of an aeroplane and accelerates uniformly at 9.8 ms-2 for ten seconds. a. How far does she tra

Mrac [35]

Answer:

a.) 490m

b.) 98m/s

Explanation:

Given that the

Acceleration g = 9.8 m/s^2

Time = 10s

Since the parachutist jumps out of an aeroplane. The parachutist jumped out from rest. Initial velocity U is therefore equal to zero. That is,

U = 0

Distance covered = height H

The height can be calculated by using second equation of motion

H = Ut + 1/2gt^2

Substitute g and t into the formula

H = 1/2 × 9.8 × 10^2

H = 490 m

Therefore, she travels as far as 490 m

b.) Her final velocity can be calculated by using third equation of motion

V^2 = U^2 + 2gH

Substitute g and H into the formula.

Remember that U = 0

V^2 = 2 × 9.8 × 490

V^2 = 9604

V = sqrt (9604)

V = 98 m/s

Therefore, her final velocity is 98 m/s

4 0

3 years ago