Answer:
Assuming your equations are:
x-3y=3
4x+3y=-3
The answers are x = 0 and y = -1.
See the image for the graph.
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Step-by-step explanation:
See the image for the graph.
Answer:
I am not in your grade that Is way to hard
Answer:
It would be a obtuse triangle instead
Step-by-step explanation:
By using pythagorean and theorem (a^2 + b^2 = c^2)
So it would be 13^2___2^2 + 12^2
When you square them, you get 169___4 + 144
144 + 4 = 148, which is less than 169
SO it would be 169>148
So no, not a right triangle
Answer:
the ones are options 2 and 3
Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
Answer link
Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
Answer link
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