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beks73 [17]
3 years ago
6

Which statement described a force between charged particles

Physics
1 answer:
pickupchik [31]3 years ago
8 0
Your answer is Coulomb's Law. The equation that describes it is:

F_e = K\cdot \frac{Q_1\cdot Q_2}{d^2}
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Which explains the downward force produced when air flows over the winglike spoiler on a race car?
professor190 [17]
Newton's principle
newton's 2nd law of motion where F=ma
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3 years ago
Ball X of mass 1.0 kg and ball Y of mass 0.5kg travel toward each other on a horizontal surface. Both balls travel with a consta
bazaltina [42]

Answer:

B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.

Explanation:

Impulse created by ball Y  on ball X = 40 x 1/6 Ns

Ball X will also create impulse 40 / 6 on ball Y .

impulse = change in momentum .

impulse in Y = change in momentum in Y .

Initial momentum of Y  = .5 x 5 = 2.5

Let final velocity of Y after collision be v  in opposite direction .

change in momentum of Y = v - (-2.5 )

so,

v + 2.5 = 40 / 6 =  6.67

v =  4.17 m / s .

Option B is correct .

B. Ball Y will travel at a speed less than 5 m/s in the opposite direction of travel as before the collision.

4 0
3 years ago
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An eagle carrying a trout flies above a lake along a horizontal path. The eagle drops the trout from a height of 6.1 m. The fish
Snezhnost [94]

Answer:

7.1 m/s

Explanation:

First, find the time it takes for the fish to reach the water.

Given in the y direction:

Δy = 6.1 m

v₀ = 0 m/s

a = 9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

6.1 m = (0 m/s) t + ½ (9.8 m/s²) t²

t = 1.12 s

Next, find the velocity needed to travel 7.9 m in that time.

Given in the x direction:

Δx = 7.9 m

a = 0 m/s²

t = 1.12 s

Find: v₀

Δx = v₀ t + ½ at²

7.9 m = v₀ (1.12 s) + ½ (0 m/s²) (1.12 s)²

v₀ = 7.1 m/s

4 0
4 years ago
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20. Consider two Stars A and B with temperatures Ta and TB and radii Ra and RB respectively. If TA
Rus_ich [418]

Answer:

L_A = 9 L_B

Explanation:

The formula that relates the luminosity of a star (L) to its radius (R) and the temperature (T) is

L=\frac{R^2}{T^4}

For star B, we can write:

L_B=\frac{R_B^2}{T_B^4}

For star A, we have

T_A = 2 T_B\\R_A = 12 R_B

So the luminosity of star A is

L_A=\frac{R_A^2}{T_A^4}=\frac{(12 R_B)^2}{(2 T_B)^4}=\frac{144 R_B^2}{16 T_B^4}=9\frac{R_B^2}{T_B^4}=9 L_B

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3 years ago
Animals need oxygen to complete the many chemical reactions taking place in the body. An animal inhales oxygen and exhales _____
mezya [45]
Carbon dioxide and nitrogen
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