Answer:
Answer: Energy from the sun.
Explanation:
<em>If you look at the hints it says that it needs something else for a plant to grow and what does a plant need? </em>
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<em>Air, Water, and energy from the Sun to make food</em>
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<em>Hope this helps :)</em>
Filtration is useful for separating sediments that are carried in water for easy drinking without the risk of disease - an example of this is a water purifier
The IUPAC names of the organic compounds would be as follows:
1. Methanol or 1-Methanol
2. Propan-2-ol or 2-Propanol
3. 2-MethylButane
4. 1-Hexanol
5. 1-Heptanol
<h3>Naming organic compounds</h3>
In the naming of organic compounds, some fundamental rules come into practice. Some of these rules include:
- The longest carbon chain, otherwise known as the parent chain, is considered.
- The substituents must be identified
- The parent chain should be named such that the substituents are located on the lowest-numbered carbons. Repeated substituents are named accordingly.
- Different substituents are named alphabetically and substituents with lower alphabets are considered for the lowest-numbered carbons.
Following these rules and more, the name of the organic compounds whose structures are shown in the image would be as follows:
- Methanol or 1-Methanol
- Propan-2-ol or 2-Propanol
- 2-MethylButane
- 1-Hexanol
- 1-Heptanol
More on IUPAC naming can be found here: brainly.com/question/16631447
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Just simply... they both are energy.
Use a bow and arrow as an example:
When you pull back an arrow, potential energy or PE is stored in the string and the limbs of the bow.
When you release the the arrow, energy is being transferred from the bow to the arrow. The arrow now has kinetic energy or KE, this means that the energy is being used by the arrow.
Answer:
W = - 10.5943 KJ, work is negative because it is carried out by the system towards the surroundings.
Explanation:
heat engine:
∴ Th = 485°C
∴ Tc = 42°C
∴ Qh = 9.75 KJ......heat from hot source
first law:
∴ ΔU = Q + W = 0 .........cyclic process
⇒ Q = - W
∴ Q = Qh + Qc = Qh - (- Qc)
∴ Qc: heat from the cold source ( - )
⇒ Qh - ( - Qc) = - W..............(1)
⇒ Qc/Qh = - Tc/Th...........(2)
from (2):
⇒ Qc = - (Tc/Th)(Qh) = - (42°C/485°C)(9.75 KJ)
⇒ Qc = - 0.8443 KJ
replacing in (1):
⇒ - W = 9.75 KJ - ( - 0.8443 KJ)
⇒ - W = 10.5943 KJ