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3 years ago

If pollution is increased, then the cricket frog population will (increase/decrease/stay the same) over the span of five years.

Chemistry

2 answers:

stepladder [879]3 years ago

4 0

I am guessing it will decrease

rjkz [21]3 years ago

3 0

I think that the population will decrease.

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What did Zoya and her freind do in response

Mama L [17]

In response of what like what’s the full clear question

5 0

3 years ago

Water is poured into a conical container at the rate of 10 cm3/sec. The cone points directly down, and it has a height of 20 cm

8090 [49]

Answer:

\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{2}

Explanation:

Hello,

The suitable differential equation for this case is:

$\frac{dV}{dt}=10\frac{cm^3}{s}$

As we're looking for the change in height with respect to the time, we need a relationship to achieve such as:

$\frac{dh}{dt} = ?*\frac{dV}{dt}$

Of course, $?=\frac{dh}{dV}$ .

Now, since the volume of a cone is $V=\pi r^2h/3$ and the ratio $r/h=15/20=3/4$ or $r=3/4h$ , the volume becomes:

$V=\pi (\frac{3}{4} h)^2h/3= \frac{3}{16}\pi h^3$

We proceed to its differentiation:

$\frac{dV}{dh} =\frac{9}{16} \pi h^2\\\frac{dh}{dV} =\frac{16}{9 \pi h^2}$

Then, we compute $\frac{dh}{dt}$

$\frac{dh}{dt} = \frac{16}{9 \pi h^2}*\frac{dV}{dt}\\\frac{dh}{dt} = \frac{16}{9\pi h^2}*10\frac{cm^3}{s} =\frac{160}{9 \pi h^2}$

Finally, at h=2:

$\frac{dh}{dt}_{h=2cm} =\frac{160}{9\pi 2^2}\\\frac{dh}{dt}_{h=2cm} =\frac{40}{9\pi}\frac{cm}{s}$

Best regards.

4 0

3 years ago

Pls help me ASAP thank you!!

Stolb23 [73]

Sorry i cant even read that

7 0

3 years ago

The answer please thank you

otez555 [7]

Answer:

Explanation:

5 0

3 years ago

A complex absorbs photons with an energy of 4.10×10^−19 J. What is the wavelength of these photons? If this is the only place in

MaRussiya [10]

Answer:

483 nm corresponds to blue light hence the complex will appear orange.

Explanation:

Using the formula;

E= hc/λ

Where;

E = energy of the photon

h = Plank's constant (6.6*10^-34Js)

c = Speed of light (3*10^8 ms-1)

λ = wavelength

λ = hc/E

λ = 6.6*10^-34 * 3*10^8/4.10×10^−19

λ = 4.83 * 10^-7 or 483 nm

483 nm corresponds to blue light

Using the colour wheel approach, if a complex absorbs blue light, then it will appear orange.

6 0

2 years ago