Answer:
DECREASE BY A FACTOR OF FOUR
Explanation:
Using pressure equation:
P 1 / T1 = P2 /T2 (at constant volume)
P1 = P
T1 =T
P2 = ?
T2 = 4 T
So therefore;
P2 = P1T1/ T2
P2 = P T/ 4 T
P2 = 1/4 P
The pressure is decreased by a factor of four, the new pressure is a quarter of the formal pressure of the gas.
The change in energy of the system : -63 J
<h3>Further explanation</h3>
Given
279 J work
216 J heat
Required
The change in energy
Solution
Laws of thermodynamics 1
ΔU=Q+W
Rules :
- receives heat, Q +
- releases heat, Q -
- work is done by a system, W -
- work is done on a system, W +
a gas work on the surrounding : W =-279 J
a gas absorb heat from surrounding : Q = +216 J
Internal energy :
= -279+216
= -63 J
I think the answer is
Reduce friction
:)
The sign of the entropy change, ΔS, for the following processes include:
- I2 (s) + ½ Cl2 (g) ← → ICl (g) - positive
- 3 Ag (s) + 4 HNO3 (aq) → 3AgNO3 (aq) + NO (g) + 2 H2O (l) - positive
- Cl2 (g) → Cl2 (l) - negative
- C5H12 (g) + 8 O2 (g) → 5 CO2 (g) + 6 H2O (l) - negative
What is Entropy?
This is referred to the degree of randomness or disorderliness of a system and is denoted as S.
Entropy change is usually positive when solid or liquid reactant is converted into gas product and vice versa.
Read more about Entropy here brainly.com/question/419265
#SPJ1
Answer:
Absolute error 
% Error 
5
Explanation:
The absolute error is the the difference in the measured value and the actual value of a quantity.
Here the actual value is 
grams
The measured value is 
grams
Absolute error
Percent error
Where AE stands for absolute error and AV stands for absolute value.
%
