The mixing ratio is 6.
To find the answer, we have to know about the mixing ratio.
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What is mixing ratio?</h3>
- The mixing ratio must be calculated in a complex manner.
- A saturated vapor pressure (es) for values of air temperature and an actual vapor pressure (e) for values of dewpoint temperature must be determined in order to determine the mixing ratio.
- The air temperature and/or dewpoint temperature must first be converted to degrees Celsius (°C) before the vapor pressures can be calculated.
- The equation below can be used to determine the relative humidity (rh), as well as the actual mixing ratio and saturated mixing ratio,
where; w is the mixing ratio and w(s) is the saturation mixing ratio.
- In our question, it is given that,
- Thus, the mixing ratio will be,
Thus, we can conclude that, the mixing ratio is 6.
Learn more about mixing ratio here:
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Your teacher is right. The moon can be seen early in the morning sometimes and late at night. Different phases are only visible on certain days as one day might be full quarter, the next full moon, the next first quarter, etc.
Answer:
The frog's horizontal velocity is 0.2 m/s.
Explanation:
To solve this problem, we must first remember what velocity is and how we solve for it. Velocity can be solved for using the formula x/t, where x represents horizontal distance and t represents time (in seconds), that it takes to travel this distance. If we plug in the given numbers for these variables and solve, we get the following:
v = x/t
v = 0.8m/4s
v = 0.2 m/s
Therefore, the correct answer is 0.2 m/s. We can verify that these units are correct because the formula calls for distance divided by time, so meters per second is a sensible answer.
Hope this helps!
Answer:
28 degree C
Explanation:
We are given that
We have to find the temperature on a spring day when resistance is 215.1 ohm.
We know that
Using the formula
Hence, the temperature on a spring day 28 degree C.
Answer:
2,500 Joules (J) or Newton Meter (N M)
Explanation:
Work = Force x Distance
The force in this equation is 500 Newtons. The distance (displacement) is 5 meters. Plug it into the equation above.
Work = 5m x 500n
Work = 2,500 Joules or Newton-Meters.
Therefore 2,500 Joules or Newton Meters of work is done on an object.
