Hclo is a weak acid (ka = 4.0 × 10–8) and so the salt naclo acts as a weak base. what is the ph of a solution that is 0.089 m in
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Answer:
The answer to your question is P = 1.357 atm
Explanation:
Data
Volume = 22.4 L
1 mol
temperature = 100°C
a = 0.211 L² atm
b = 0.0171 L/mol
R = 0.082 atmL/mol°K
Convert temperature to °K
Temperature = 100 + 273
= 373°K
Formula
Substitution
Simplify
(P + 0.0094)(22.3829) = 30.586
Solve for P
P + 0.0094 =
P + 0.0094 = 1.366
P = 1.336 - 0.0094
P = 1.357 atm