Answer:
after t = 3 hours compound A remain 0.396 M
t = 12.98 hours
Explanation:
P = P_0*e^(-kt)
t = 30 minutes = 30/60 hours = 0.5 hours
and P_0 = 0.60M
and P after t = 0.5 hours is 0.56 M
(0.56/0.6) = e^(-kt)
0.933 =e^(-kt)
k = 0.138
P = P_0*e^(-0.138t)
Now after t = 3 hours,
P = 0.6* e^((-0.138)*3) = 0.396 M
time when P = 0.1 M
0.1 = 0.6*e^(-0.138t)
t = 12.98 hours
Answer:
692.31 N
Explanation:
Applying,
F = ma............... Equation 1
Where F = Average force required to stop the player, m = mass of the player, a = acceleration of the player
But,
a = (v-u)/t............ Equation 2
Where v = final velocity, u = initial velocity, t = time.
Substitute equation 2 into equation 1
F = m(v-u)/t............ Equation 3
From the question,
Given: m = 75 kg, u = 6.0 m/s, v = 0 m/s (to stop), t = 0.65 s
Substitute these values into equation 3
F = 75(0-6)/0.65
F = -692.31 N
Hence the average force required to stop the player is 692.31 N
Answer:
<em>The</em><em> </em><em>net</em><em> </em><em>force</em><em> </em><em>on</em><em> </em><em>the</em><em> </em><em>hockey</em><em> </em><em>puck</em><em> </em><em>is</em><em> </em><em>zero</em><em> </em><em>because</em><em> </em><em>it's </em><em>acceleration</em><em> </em><em>is</em><em> </em><em>zero</em><em> </em><em>due to </em><em>constant</em><em> </em><em>velocity</em><em>.</em>
<em>The</em><em> </em><em>hockey</em><em> </em><em>will</em><em> </em><em>remain</em><em> </em><em>in</em><em> </em><em>it's </em><em>uniform </em><em>motion</em><em> </em><em>unless</em><em> </em><em>compelled</em><em> </em><em>by</em><em> </em><em>an</em><em> </em><em>exter</em><em>nal</em><em> </em><em>force</em><em>.</em>
Explanation:
![from \: vector \: mechanics \\ a = \frac{dv}{dt} \\ but \: at \: constant \: velocity \\ \frac{dv}{dt} = 0 \\ hence : \: \: a = \frac{0}{dt} \\ a = 0](https://tex.z-dn.net/?f=from%20%5C%3A%20vector%20%5C%3A%20mechanics%20%5C%5C%20a%20%3D%20%20%5Cfrac%7Bdv%7D%7Bdt%7D%20%20%5C%5C%20but%20%5C%3A%20at%20%5C%3A%20constant%20%5C%3A%20velocity%20%5C%5C%20%20%5Cfrac%7Bdv%7D%7Bdt%7D%20%20%3D%200%20%5C%5C%20hence%20%3A%20%20%5C%3A%20%20%5C%3A%20a%20%3D%20%20%5Cfrac%7B0%7D%7Bdt%7D%20%20%5C%5C%20a%20%3D%200)
The only statement which is true is:
<span>In a series circuit, the resistors do not share the current.
In fact, when resistors are put in series, the current I crosses all the resistors with same intensity, and so the resistors are all crossed by the same value of the current.</span>
Greenhouse gases, eg. carbon dioxide and methane.