Answer:
46g of sodium acetate.
Explanation:
The data is: <em>Precipitation from a supersaturated sodium acetate solution. The solution on the left was formed by dissolving 156g of the salt in 100 mL of water at 100°C and then slowly cooling it to 20°C. Because the solubility of sodium acetate in water at 20°C is 46g per 100mL of water, the solution is supersaturated. Addition of a sodium acetate crystal causes the excess solute to crystallize from solution.</em>
The third solution is the result of the equilibrium in the solution at 20°C. As the maximum quantity that water can dissolve of sodium acetate at this temperature is 46g per 100mL and the solution has 100mL <em>there are 46g of sodium acetate in solution. </em>The other sodium acetate precipitate because of decreasing of temperature.
I hope it helps!
Answer:
Bromine mollecules are held together by van der waals forces while a water molecule constitutes both van der waals forces and hydrogen bomnding
Explanation:
This makes the water molecule recquire more heat energy to break the bond thus a higher boiling point while bromine structure requires just litttle heat energy
Answer:
Less than one gram
Explanation:
Since there is no whole number before the decimal it means that the number is less than whole meaning it is less than one gram
Answer:
For example, when we bake a cake, it's a result of a mixture of eggs, flour, sugar, and other ingredients. Any time two or more items are combined, a mixture is formed. Sometimes, the different parts of a mixture can be separated into individual entities. Other times, they're married for as long as they exist.
Explanation:
Answer:
Explanation:
Your B-L Acid is a proton (Hydrogen, H+) donor, and your B-L base is a proton acceptor. This means that the base will take a hydrogen from your acid. NO2- is a B-L base, and you can tell it is a base by the negative charge it possesses. This means that it has a lone pair that wants to grab one of the hydrogens from NH4+, the B-L acid. In scientific words, the NO2- is a nucleophile and NH4+ is an electrophile. The result of NO2- grabbing that hydrogen from NH4+ is that NO2- becomes HNO2 (your conjugate acid) and and NH4+ becomes NH3 (you conjugate base). Basically, any time a B-L acid loses a proton, its equal product will be its conjugate base, and any time a B-L base gains a proton, its equal product will be its conjugate acid.
I hope this helped explain the concept behind Bronsted-Lowry acids and bases! Good luck with your class and please don't forget to give a positive rating! :-)