Answer: There is 125 mL of a 2.0 M CuCl2 solution are needed to make 500 mL of a 0.5 M solution
Explanation:
Given:
= 2.0 M,
= ?
= 0.5 M,
= 500 mL
Formula used to calculate the volume is as follows.
![M_{1}V_{1} = M_{2}V_{2}](https://tex.z-dn.net/?f=M_%7B1%7DV_%7B1%7D%20%3D%20M_%7B2%7DV_%7B2%7D)
Substitute the values into above formula as follows.
![M_{1}V_{1} = M_{2}V_{2}\\2.0 M \times V_{1} = 0.5 M \times 500 mL\\V_{1} = 125 mL](https://tex.z-dn.net/?f=M_%7B1%7DV_%7B1%7D%20%3D%20M_%7B2%7DV_%7B2%7D%5C%5C2.0%20M%20%5Ctimes%20V_%7B1%7D%20%3D%200.5%20M%20%5Ctimes%20500%20mL%5C%5CV_%7B1%7D%20%3D%20125%20mL)
Thus, we can conclude that there is 125 mL of a 2.0 M
solution are needed to make 500 mL of a 0.5 M solution.
<h2>Halogens.</h2>
Explanation:
All of the halogens form salts with alkali metals with the formula MX.
Halogens are the members of group 17 in the periodic table. They have seven electron in their valence shell and tend to form negative ion with minus one charge. They get there name because of their property to form salts. Halogens are very reactive and form salts with the metals.
Answer is 355 grams.
Explanation:
Given the molecular weights:
M
r
N
a
O
H
=
40
g
m
o
l
M
r
N
a
2
S
O
4
=
142
g
m
o
l
The analogy of the moles will be held constant:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
1
n
N
a
O
H
n
N
a
2
S
O
4
=
2
For each one, substitute:
n
=
m
M
r
Therefore:
n
N
a
O
H
n
N
a
2
S
O
4
=
2
m
N
a
O
H
M
r
N
a
O
H
m
N
a
2
S
O
4
M
r
N
a
2
S
O
4
=
2
200
40
x
142
=
2
200
⋅
142
40
x
=
2
200
⋅
142
=
2
⋅
40
x
x
=
200
⋅
142
2
⋅
40
=
100
⋅
142
40
=
10
⋅
142
4
=
1420
4
=
=
710
2
=
355
g
r
a
m
s
(or just use a calculator)
Hello there.
<span>
Some elementary particles are positively or negatively
</span><span>
b. charged particles.
</span>