Answer:
b. Extraction with a solution of sodium hydrogen carbonate, separating the layers, followed by drying and evaporating the organic layer.
Step-by-step explanation:
The ether solution contains your product, benzaldehyde, and some starting material, benzoic acid, the purification steps are:
- Extract with a solution of NaHCO₃. The ether layer contains benzaldehyde, and the aqueous layer contains sodium benzoate.
- Separate the layers. Keep the ether layer.
- Dry the ether solution.
- Distill the ether (boiling point 35 °C) and purify the benzaldehyde (178 °C) by steam distillation.
a. is wrong. Extraction with HCl will not remove much of the benzoic acid.
c. is wrong. If you evaporate the organic layer, you will have a mixture of benzaldehyde and benzoic acid.
d. is wrong. If you work with the aqueous layer, you will end up with benzoic acid,
Hey there!:
HA <=> H⁺ + A⁻
pH = -log[H+] = 6
[ H⁺ ] = 10^-pH
[ H⁺] = 10 ^ -6
[ H⁺ ] = 0.000001 M
Percent dissociation:
[ H⁺ ] / [ HA]o * 100
[ 0.000001 / 0.10 ] * 100
0.00001 * 100 => 0.0010%
Answer D
Hope that helps!
Answer:
5 × 10^-4 L
Explanation:
The equation of the reaction is;
2KClO3 = 2KCl + 3O2
Number of moles of KClO3 = 13.5g/122.5 g / mol = 0.11 moles
From the stoichiometry of the reaction;
2 moles of KClO3 yields 3 moles of O2
0.11 moles of KClO3 yields 0.11 × 3/2 = 0.165 moles of oxygen gas
From the ideal gas equation;
PV= nRT
P= 85.4 × 10^4 KPa
V=?
n= 0.165
R= 8.314 J K-1 mol-1
T= 40+273 = 313K
V= 0.165 ×8.134 × 313/85.4 × 10^4
V=429.4/85.4 × 10^4
V= 5 × 10^-4 L
I think its c because solid,liquid nor plasma really fits to the description and i don't really know the last one so the best option is probably C.
