If you have a rectangular space with dimensions of 200 ft. x 85 ft., and 32,500 square feet is required by 65 cars, do you have
sufficient space for 86 cars?
2 answers:
No, you can not fit 86 cars
I believe it is no. There is no way it can fit that many cars.
You might be interested in
Answer:
6x
Step-by-step explanation:

Square of 36 is 6. Square of x^2is x.

Answer:
g(-5) = -127
Step-by-step explanation:
Plug in -5 for x:
g(-5) = (-5)^3 - 2
= -125 - 2
= -127
Answer: m=-1.
Step-by-step explanation:

Answer 16(67)-10
Step-by-step explanation:
Answer:
22 and 46
Step-by-step explanation:
let
one number is x
another is 2x+2
now 2x+2+x=68
or, 3x+2=68
3x=66
or x=66/3=22
so one number is 22 and another is (22X2+2)=46